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olasank [31]
2 years ago
7

A tennis ball is hit into the air with a racket. when is the ball’s kinetic energy the greatest? ignore air resistance.

Physics
1 answer:
krok68 [10]2 years ago
4 0

When the player strikes the ball, kinetic energy is at its greatest.

Kinetic energy = 1/2*m*v^{2}

where m denotes mass and v denotes velocity.

Therefore, kinetic energy is inversely correlated with square of velocity.

When a player strikes the ball, velocity is at its highest.

Thus, when the player strikes the ball, kinetic energy is at its highest.

<h3>What is kinetic energy?</h3>

It is the energy that a body has because it is moving.

<h3>Which 5 forms of kinetic energy are there?</h3>

Kinetic energy comes in five different forms:

  • radiant
  • thermal
  • sound
  • electrical
  • mechanical.

Kinetic energy is measured in Joules.

Importance of kinetic energy:

  • The capacity to perform work is kinetic energy's most significant quality.
  • Force acting on an object while it is moving is referred to as work.
  • Energy and work are interchangeable because of their tight relationship.

To learn more about kinetic energy visit:

brainly.com/question/12669551

#SPJ4

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If y(t)y(t) describes the position with time, what is the proper formula for velocity with time? (Recall velocity is related to
PilotLPTM [1.2K]

Answer:

Although this question is not complete, I would give a general solution to this kind of problems.

If y(t) describes the position of a body with time such that

y(t) = at^(n) + bt^(m) + C

Then

V(t) = dy(t)/dt = ant^(n-1) + bmt^(m-1)

Explanation:

As an example supplies the position of a particle is given by

y(t) = 4t³- 3t² + 9

V(t) = 4x3t²- 3x2t¹

V(t) = d(t)/dt = 12t² - 6t.

Another example,

If y(t) = 15t³ - 2t² + 30t -80

V(t) = d(t)/dt = 15x3t² - 4t +30 = 45t² + 4t + 30.

Basically, in the equations above the powers of t reduces by one when computing the velocity function from y(t) by differentiation (calculating the derivative of y(t)). The constant term C (9 and 80 in the functions of y(t) in examples 1and 2 above) reduces to zero because the derivative of a constant (and ordinary number without the t attached to it) is always zero.

One last example,

y(t) = 2t^6 -3t²

V(t) = d(t)/dt = 12t^5 - 6t

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a car takes off from rest and covers a distance of 80m on a straight road in 10s.calculate the magnitude of its acceleration
olasank [31]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Here's the solution :

Let's find the final velocity :

  • \dfrac{displacement}{time}

  • \dfrac{80}{10}

  • 8 \:  \: ms {}^{ - 1}

Initial velocity (u) = 0 (cuz it started from rest)

Final velocity (v) = 8 m/s

Time taken (t) = 10 sec

now, we know that :

  • acceleration =  \dfrac{v - u}{t}

  • \dfrac{8 - 0}{10}

  • \dfrac{8}{10}

  • 0.8 \:  \: m {s}^{ - 2}

Acceleration = 0.8 m/s²

7 0
3 years ago
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