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kati45 [8]
3 years ago
13

A small plane is initially flying due west with an airspeed (speed relative to the air) of 50 m/s. the plane flies into a-region

where the wind is blowing toward the southwest at 20 m/s. if the pilot does not change the heading of the plane, the speed of the plane relative to the ground
a. is greater than
Physics
1 answer:
Norma-Jean [14]3 years ago
5 0

velocity of plane with respect to air is given as 50 m/s towards west

v_{p/w} = 50 (-i)

now speed of the wind is given as 20 m/s south west

v_{w} = 10\sqrt{2}(-i) + 10\sqrt{2}(-j)

now the net speed with respect to ground is given as

v_{net} = v_w + v_{p/w}

v_{net} = 10\sqrt2(-i) + 10\sqrt2(-j) + 50(-i)

v_{net} = 64.14(-i) + 14.14(-j)

so this speed with respect to ground is 65.7 m/s

this is greater than the speed with respect to air

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Newton's first law of inertia: When an objects is in state of motion, it will remain its state of motion or if it is in state of rest then it will remain in rest unless it is acted upon by external motion.

In the given options, a ball sits motionless on the ground is good example of Newton's first law motion. No external force is acting in this case.

In options (B), (C) and (D) , the external force is acting.

Therefore, the correct option is A.

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Explanation:

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The amount of heat that the second fluid (water) releases is equal to the amount of heat that the first fluid (water) receives in this spontaneous process.

Q₁ = Q₂

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m₁ c (t - t₁)  = m₂ c (t₂ - t) \ : c

Since water is the liquid in question, it has the same specific heat capacity. Therefore, we will divide both sides of the equation by c and get:

m₁ (t - t₁)  = m₂ (t₂ - t) =>  m₂ = m₁ (t - t₁) / (t₂ - t) =>

m₂ = 750 · (75 - 10) / (100 - 75) => m₂ = 750 · 65 / 25 = 1,950 g

m₂ = 1,950 g

God is with you!!!

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sashaice [31]

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Genrish500 [490]

The question is incomplete. The complete question is :

If the entire population of Earth were transferred to the Moon, how far would the center of mass of the Earth-Moon population system move? Assume the population is 7 billion, the average human has a mass of 65 kg, and that the population is evenly distributed over both the Earth and the Moon. The mass of the Earth is 5.97×1024 kg and that of the Moon is 7.34×1022 kg. The radius of the Moon’s orbit is about 3.84×105 m.

Solution :

Given :

Mass of earth, $M_e = 5.97 \times 10^{24} \ kg$

Mass of moon, $M_m = 7.34 \times 10^{22} \ kg$

Mass of each human, $m_p =65 \ kg$

Therefore mass of total population, $M_p = 65  \times 7 \times 10^{9} \ kg$

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Let the earth is at the origin of the coordinate system. Then,

Since $M_e>> M_p$

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Hence if we shift all the population on the moon there will be negligible change in the mass of the moon and earth. Hence there will not be any significant shift on the centre of mass. i.e.

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              $= 4.68 \times 10^6 \ m$

$ 4.68 \times 10^3 \ km$ from the earth.

         

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