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mojhsa [17]
3 years ago
12

Three treatments of different starting materials are listed. Which statement explains the treatments? Substance 1 was activated

by a decrease in temperature, Substance 2 was activated by the change in concentration, and Substance 3 decreased the surface area. Substance 1 was activated by a decrease in temperature, Substance 2 was activated by the change in pressure, and Substance 3 increased the surface area. Substance 1 was activated by the heat and inactivated by ice, Substance 2 was activated by the change in pressure, and Substance 3 decreased the surface area. Substance 1 was activated by the heat and inactivated by ice, Substance 2 was activated by the change in concentration, and Substance 3 increased the surface area.
Chemistry
2 answers:
IrinaVladis [17]3 years ago
9 0

the answer is d, cause im smart lol

iren2701 [21]3 years ago
8 0
<span> Substance 1 was activated by the heat and inactivated by ice, Substance 2 was activated by the change in concentration, and Substance 3 increased the surface area.</span>
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How much heat is released when 15.7g of methane (c2h6) is combusted if the enthalpy of the reaction is - 1560.7 kj
lyudmila [28]

- 407.4 kJ of heat is released.

<u>Explanation:</u>

We have to write the balanced equation as,

2 C₂H₆(g) + 7O₂ → 4CO₂ + 6H₂O

Here 2 moles of ethane reacts in this reaction.

Now we have to find out the amount of ethane reacted using its given mass and molar mass as,

2 mol C₂H₆ × 30.07 g of C₂H₆ / 1 mol C₂H₆ = 60.14 g of C₂H₆

Heat released = ΔH × given mass / 60.14

                        = - 1560. 7 kj ×15.7 g / 60. 14 g  = -407. 4 kJ

5 0
3 years ago
Identify the effect of increasing acidity on the solubility of the given compounds.
Ilia_Sergeevich [38]

All the given compounds are basic on acidifying their solubility increases.

<u>Explanation:</u>

  • C a_{3}\left(P O_{4}\right)_{2} solubility will increase, since it is basic in nature, on acidifying  solubility increases.
  • F e S being basic on acidification, the solubility increases.
  • M g C O_{3} is alkaline in nature, it gets neutralized and there is no increase in acidity.
  • M g B r_{2} is a salt and it shows no effect on acidification.
  • A g I is a salt but insoluble in water and shows no effect on acidification.
  • M g(O H)_{2} is strongly basic in nature, on acidifying the solubility increases.
4 0
4 years ago
Can anyone help me please?
Nady [450]

10. Is A

11. Is D

12. Is D

13. Is B

5 0
3 years ago
How many milliliters of 0.100 m naoh are required to neutralize 9.00 ml of 0.0500 m hcl?
BabaBlast [244]
V  ( NaOH ) = mL ?

M ( NaOH ) = 0.100 M

V ( HCl ) = 9.00 mL / 1000 => 0.009 L

M ( HCl ) = 0.0500 M

number of moles HCl:

n = M x V

n = 0.009 x 0.0500 => 0.00045 moles HCl

mole ratio:

<span>HCl + NaOH = NaCl + H2O
</span>
 1 mole HCl ---------------- 1 mole NaOH
 0.00045 moles HCl ----- ??

0.00045 x 1 / 1 => 0.00045 moles of NaOH

M = n / V

0.100 = 0.00045 / V

V = 0.00045 / 0.100

V = 0.0045 L

1 L ------------ 1000 mL
0.0045 L ----- ??

0.0045 x 1000 / 1 => 4.5 mL of NaOH



6 0
4 years ago
What does variable mean
DedPeter [7]
In an experiement things that are changing are called variables.
4 0
3 years ago
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