Three treatments of different starting materials are listed. Which statement explains the treatments? Substance 1 was activated
2 answers:
You might be interested in
Answer:
30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.
Explanation:
Let volume of the 40% acid solution be x.
Let volume of the 60% acid solution be y.
Volume of solution formed after mixing both solution = 40 L
x + y = 40 L..[1]
Volume of acid 40% solution = 40% of x= 0.4x
Volume of acid 60% solution = 60% of y= 0.6y
Volume of acid formed = 45% of 40 L =
..[2]
Solving [1] and [2]
x = 30 L , y = 10 L
30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.
Answer:
280 g
Explanation:
Let's consider the decomposition of ammonium nitrate.
NH₄NO₃(s) ⇒ N₂(g) + 0.5 O₂(g) + 2 H₂O(g)
We can establish the following relations:
- The molar mass of NH₄NO₃ is 80.04 g/mol.
- The molar ratio of NH₄NO₃ to N₂ is 1:1.
- The molar mass of N₂ is 28.01 g/mol.
The mass of N₂ produced when 800 g of NH₄NO₃ react is: