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Assoli18 [71]
3 years ago
14

How many milliliters are in 3.2 L? (1000 mL = 1L)

Physics
2 answers:
navik [9.2K]3 years ago
7 0

Answer: 3200ml.

Please give brainliest.

likoan [24]3 years ago
5 0

Answer:

3200ml

Explanation:

(3.2L)\frac{1000mL}{1L} = 3200mL

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It turns out that Mercury and Mars have the same gravity as one another – that is, you would weigh the same on the surface of Me
Tamiku [17]

Answer:

Explanation:

The value of acceleration due to gravity of mars is same as that the value of acceleration due to gravity of Mercury.

The value of acceleration due to gravity of a planet depends on its mass and the radius.

The formula for the acceleration due to gravity is given by

g=\frac{GM}{R^{2}}

Where, M be the mass of the planet, R be the radius of the planet.

As according to the question, the value of acceleration due to gravity for Mercury is same as that of Mars.

\frac{GM_{mercury}}{R_{mercury}^{2}}=\frac{GM_{mars}}{R_{mars}^{2}}

\frac{M_{mercury}}{R_{mercury}^{2}}=\frac{M_{mars}}{R_{mars}^{2}}

As teh radius of Mercury is small, and acceleration due to gravity is same, it is possible because the mass of Mercury is more than the mass of Mars.

4 0
3 years ago
According to the third law of motion when we put an object, the object pushes back on us with an equal and opposite force. If th
vichka [17]


Hi pupil Here's Your answer :::


➡➡➡➡➡➡➡➡➡➡➡➡➡


Student's justification is not correct. Two equal and opposite force cancel each other if the act on the same body. According to the third law of motion action and reaction forces are equal and opposite but they both act on different bodies. Hence, they cannot cancel each other.

When we push a message track, then the applied force on the truck is not sufficient to overcome the force of friction between the tyres of truck and ground, hence, truck does not move.


⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅



Hope this helps .
5 0
3 years ago
I have a problem in this questions?
photoshop1234 [79]

Answer:

8.46E+1

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = 39 C

Charge 2 (q₂) = –53 C

Force (F) of attraction = 26×10⁸ N

Electrical constant K) = 9×10⁹ Nm²/C²

Distance apart (r) =?

The distance between the two charges can be obtained as follow:

F = Kq₁q₂ / r²

26×10⁸ = 9×10⁹ × 39 × 53 / r²

26×10⁸ = 1.8603×10¹³ / r²

Cross multiply

26×10⁸ × r² = 1.8603×10¹³

Divide both side by 26×10⁸

r² = 1.8603×10¹³ / 26×10⁸

r² = 7155

Take the square root of both side

r = √7155

r = 84.6 m

r = 8.46E+1 m

7 0
2 years ago
The formulas used to analyze the horizontal and vertical motion of projectiles launched at an angle involve the use of which fun
gizmo_the_mogwai [7]

The formulas used to analyze the horizontal and vertical motion of projectiles launched at an angle involve the use of tangent, cosine and sine.

<h3>What is vertical motion of a projecile?</h3>

The vertical motion of a projectile is affected by gravity and the velocity of vertical motion given by the following formula;

Vy = Vsinθ

<h3>What is horizontal motion of a projecile?</h3>

The horizontal velocity of a projectile is given by the following formula;

Vx = Vcosθ

<h3>Direction of the motion</h3>

The direction of the motion is calculated as follows;

tanθ  = Vy/Vx

Thus, the formulas used to analyze the horizontal and vertical motion of projectiles launched at an angle involve the use of tangent, cosine and sine.

Learn more about vertical motion here: brainly.com/question/24216590

#SPJ4

4 0
2 years ago
abody starts from rest and accelerate uniformly at 8m/s/s.calculate the distance travelled by the body in 10s? ​
vagabundo [1.1K]

Explanation:

using the formula: S=ut+½gt², where u=0, S=?, g=8m/s², t=10seconds.

S=ut+½gt² ("ut" term will cancel because u=0).

=> S= ½gt²

=>S = ½×8×10²

=>S = 4×100

=>S = 400m .

Therefore, the distance traveled by the body in 10s is 400m.

hope this helps you.

6 0
2 years ago
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