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ch4aika [34]
4 years ago
14

ANSWER PLS NEED ASAP AS FAST AS HUMANLY POSSIBLE

Physics
1 answer:
Soloha48 [4]4 years ago
6 0

Answer:

Should be B

Explanation:

As the light enters the prism at an angle, the glass causes the light to travel slower. The speed is affected by the frequency of the light. So each frequency is slowed by a different amount, causing the colors to separate.

Hope this helps!

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How do the forces acting on a boat compare to the force acting on a plane ?
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Answer:

on there boat there will two main forces act 1,upthrust which comes from water and air and other side on the plane air and gravity.

Explanation:

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3 years ago
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Parts of a transverse wave include:
iris [78.8K]

Answer:

Parts of a transverse wave include:

Crest - the highest point on the wave

Trough - the lowest point on the wave

Wavelength - the distance from one crest to the next crest, or one trough to the next trough

Amplitude - the displacement of the wave from the midpoint to the highest point (crest) or the lowest point (trough)

Explanation:

Use the internet Brother

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Which movement causes day and night on Earth?
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3 years ago
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A negative charge of -0.00067 C and a positive charge of 0.00096 C are separated by 0.7 m. What is the force between the two cha
koban [17]

Answer:

<em> -11,813.87N </em>

Explanation:

According to coulombs law, the Force between the two charges is expressed as;

F = kq1q2/d²

k is the coulombs constant = 9*10⁹kg⋅m³⋅s⁻²⋅C⁻².

q1 = -0.00067 C

q2 = 0.00096 C

d  = 0.7m

Substitute into the formula:

F =  9*10^9 *  -0.00067 * 0.00096/0.7²

F = 9*10⁹*-6.7*10⁻⁴*9.6*10⁻⁴/0.49

F = -578.88*10⁹⁻⁸/0.49

F = -578.88*10/0.49

F = -5788.8/0.49

F = -11,813.87N

<em>Hence the force between the two charges is -11,813.87N </em>

6 0
3 years ago
an object is placed 15.8 cm in front of a thin converging lens with an unknown focal length. if a real image forms behind the le
storchak [24]
<span>On what:

f (is the focal length of the lens) = ? 
p (is the distance from the object to the lens) =15.8 cm
p' (is the distance from the image to the spherical lens) = 4.2 cm

</span><span>Using the Gaussian equation, to know where the object is situated (distance from the point).
</span>
\frac{1}{f} = \frac{1}{p} + \frac{1}{p'}
\frac{1}{f} = \frac{1}{15.8} + \frac{1}{4.2}
\frac{1}{f} = \frac{2.1}{33.18} + \frac{7.9}{33.18}
\frac{1}{f} =  \frac{10}{33.18}
Product of extremes equals product of means:
10*f = 1*33.18
10f = 33.18
f =  \frac{33.18}{10}
\boxed{\boxed{f = 3.318\:cm}}\end{array}}\qquad\quad\checkmark

6 0
4 years ago
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