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ch4aika [34]
3 years ago
14

ANSWER PLS NEED ASAP AS FAST AS HUMANLY POSSIBLE

Physics
1 answer:
Soloha48 [4]3 years ago
6 0

Answer:

Should be B

Explanation:

As the light enters the prism at an angle, the glass causes the light to travel slower. The speed is affected by the frequency of the light. So each frequency is slowed by a different amount, causing the colors to separate.

Hope this helps!

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An input force is applied to a 2 cm diameter piston. The piston compresses oil and is connected to a 4 cm diameter output piston
____ [38]

Answer:

4 times

Explanation:

Given:

diameter of the input piston, d_i=2\ cm=0.02\ m

diameter of the output piston, d_o=4\ cm=0.04\ m

In such mechanical arrangements the fluid acts as an incompressible link and the pressure remains uniform throughout the fluid bulk.

Then, by the Pascal's law:

\frac{F_i}{A_i} =\frac{F_o}{A_o}

where:

F_i\ \&\ F_o are the input and the output forces respectively.

A_i\ \&\ A_o are the input and the output area of pistons respectively.

\frac{F_i\times 4}{\pi.d_i^2} =\frac{F_o\times 4}{\pi.d_o^2}

\frac{F_i}{d_i^2} =\frac{F_o}{d_o^2}

\frac{F_o}{0.04^2}=\frac{F_i}{0.02^2}

F_o=4\times F_i

8 0
3 years ago
What statement is true about a spring?
Citrus2011 [14]
A spring is felxiable
5 0
4 years ago
Read 2 more answers
Sarah's group designed this oven and eventually melted the
torisob [31]

Answer:

b

Explanation:

because i don't he asking me

5 0
4 years ago
A continuous line of charge lies along the x axis, extending from x = +x0 to positive infinity. The line carries positive charge
yawa3891 [41]

Answer:

 E = k λ₀ / x₀, the field is in thenegative direction of the x axis (-x)

Explanation:

In this problem the electric field of a line of charge is requested, the expression for the electric field is

          E = k ∫ dq / r²

where k is the Coulomb constant that you are worth 9 10⁹ N m²/C², that the charge and r the distance to the point of interest, in this case it is the origin (x = 0)

let's use the definite linear density

        λ₀ = dq / dx

        dq = λ₀ dx

we replace and integrate

       E = k λ₀ ∫ dx / x²

       E = k λ₀ ( -1 / x)

we evaluate the integral from the lower limit of load x = x₀ to the upper limit x = ∞

       E = - k λ₀ (1 /∞ - 1 / x₀)

       E = k λ₀ / x₀

     

as the field is positive the direction is away from the charges, so it is in the negative direction of the x axis (-x)

7 0
4 years ago
A body of mass 70kg climbed a hill 1000m high. calculate the maximum energy gained by the body.​
stellarik [79]

Potential energy = mgh

So, energy gained

= mgh

= 70kg × (9.8m/s²) × 1000m

= 686000 kgm²/s²

= 686000 J

3 0
3 years ago
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