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GuDViN [60]
3 years ago
15

Which types of securities has the lowest priority in a bankruptcy proceeding?

Physics
1 answer:
Alex777 [14]3 years ago
4 0

Answer:

Common stock

Explanation:

Common stock is also regarded to as shares in which dividends are paid to the holders according to how profitable the organization is.

Common stock is a type of equity security and it is also the least considered in the case of bankruptcy due to its variability and the probability of stockholders not getting anything because of the debtor being insolvent.

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Give an example of each element,compound, and mixture
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Answer:An element cannot be broken down into any other substance. ... Compounds are substances made from atoms of different elements joined by chemical bonds. They can only be separated by a chemical reaction. Common examples are water (H2O), salt (sodium chloride, NaCl), methane (CH4).

Explanation:I hope this helps

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Two balloons (m = 0.021 kg) are separated by a distance of d = 16 m. They are released from rest and observed to have an instant
evablogger [386]

(a) 2.56\cdot 10^{-5} C

According to Newton's second law, the force experienced by each balloon is given by:

F = ma

where

m = 0.021 kg is the mass

a = 1.1 m/s^2 is the acceleration

Substituting, we found:

F=(0.021)(1.1)=0.0231 N

The electrostatic force between the two balloons can be also written as

F=k\frac{Q^2}{r^2}

where

k is the Coulomb's constant

Q is the charge on each balloon

r = 16 m is their separation

Since we know the value of F, we can find Q, the magnitude of the charge on each balloon:

Q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(0.0231)(16)^2}{9\cdot 10^9}}=2.56\cdot 10^{-5} C

(b) 1.6\cdot 10^{14} electrons

The magnitude of the charge of one electron is

e=1.6\cdot 10^{-19}C

While the magnitude of the charge on one balloon is

Q=2.56\cdot 10^{-5} C

This charge can be written as

Q=Ne

where N is the number of electrons that are responsible for this charge. Solving for N, we find:

N=\frac{Q}{e}=\frac{2.56\cdot 10^{-5}}{1.6\cdot 10^{-19}}=1.6\cdot 10^{14}

5 0
3 years ago
A car from the beginning was traveling at 27.8m/s when he stepped on the brakes and stopped. According to the DMV, this would le
Yuliya22 [10]

Answer:

-6.44 m/s²

Explanation:

Given:

Δx = 60 m

v₀ = 27.8 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (27.8 m/s)² + 2a (60 m)

a = -6.44 m/s²

3 0
3 years ago
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