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Semmy [17]
3 years ago
5

Es el cambio de estado en el que un sólido pasa a gaseoso sin pasar por el estado líquido o viceversa

Physics
1 answer:
Yakvenalex [24]3 years ago
8 0

Answer:

what

Explanation:

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Nancy is sailing her boat toward Sam's boat at 5
Bas_tet [7]

Answer:

Nora's boat is moving towards Sam at 5 km/hr

Explanation:

The question says that Nora is few meters behind Nancy and is still with respect to her that means the relative velocity between Nora and Nancy is zero

Vrel = 5 - Vnora= 0 ⇒ Vnora = 5km/hr

Pictorially we can represent the given condition as:

Nora-------few meters------Nancy -----------------    Sam

5km/hr                                         5km/hr →

Hence,  Nora's boat is moving towards Sam at 5km/hr.

8 0
3 years ago
Read 2 more answers
Which is brighter in our sky, a star with apparent magnitude 2 or a star with apparent magnitude 7?
Lina20 [59]

The star with apparent magnitude 2 is more brighter than 7.

To find the answer, we have to know about apparent magnitude.

<h3>What is apparent magnitude?</h3>
  • 100 times as luminous as a star with an apparent brightness of 7 is a star with a magnitude of 2.
  • The apparent magnitude of bigger stars is always smaller.
  • The brightest star in the night sky is Sirius.
  • The brightness of a star or other celestial object perceived from Earth is measured in apparent magnitude (m).
  • The apparent magnitude of an object is determined by its inherent luminosity, its distance from Earth, and any light extinction brought on by interstellar dust in the path of the observer's line of sight.

Thus, we can conclude that, the star with apparent magnitude 2 is more brighter than 7.

Learn more about the apparent magnitude here:

brainly.com/question/350008

#SPJ4

7 0
1 year ago
A student conducts an experiment in which a cart is pulled by a variable applied force during a 2 s time interval. In trial 1, t
fredd [130]

Answer:

The answer is "Including all three studies of 0s to 2s, that shift in momentum is equal".

Explanation:

Its shift in momentum doesn't really depend on the magnitude of its cars since the forces or time are similar throughout all vehicles.

Let's look at the speed of the car

F = m a\\\\a =\frac{F}{m}

We use movies and find lips

\to v = v_0 + a t\\\\\to v = v_0 + (\frac{F}{m}) t

The moment is defined by

\to p = m v

The moment change

\Delta p = m v - m v_0

Let's replace the speeds in this equation

\Delta p = m (v_0 + \frac{F}{m t}) - m v_0\\\\\Delta p = m v_0  + F t - m v_0\\\\\Delta p = F t

They see that shift is not directly proportional to the mass of cars since the force and time were the same across all cars.

5 0
3 years ago
How are eras and periods of the geologic time scale named?
Natalka [10]

Answer:

mark me brainliest plz

Explanation:

In the early 1800's a system for naming geologic time periods was devised using four periods of geologic time. They were named using Latin root words, Primary, Secondary, Tertiary and Quaternary. ... Keep in mind that this chart is focused on geologic time periods. There are also geologic Eons, Eras, and epochs.

3 0
3 years ago
Read 2 more answers
A 350-g mass is attached to a spring whose spring constant is 64 N/m. Its maximum acceleration is 5.3 m/s2. What is the frequenc
max2010maxim [7]

The frequency of oscillation is 2.153 Hz

What is the frequency of spring?

Spring Frequency is the natural frequency of spring with a weight at the lower end. Spring is fixed from the upper end and the lower end is free.

For the mass-spring system in this problem,

The Frequency of spring is calculated with the equation:

f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }

Where,

f = frequency of spring

k = spring constant = 64 N/m

m = mass attached to spring = 350g = 0.350 kg

a = maximum acceleration = 5.3 m/s^2

Substituting the values in the equation,

f = \frac{1}{2\pi } \sqrt{\frac{64}{0.350} }

f = \frac{1}{2\pi } ( 13.522)

f = 2.1535 Hz

Hence,

The frequency of oscillation is 2.153 Hz

Learn more about frequency here:

<u>brainly.com/question/13978015</u>

#SPJ4

6 0
1 year ago
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