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3 years ago

Which of the following equations are balanced?

1 answer:

6 0

A: 2H₂ + O₂ → 2H₂O

H: 4 H:4
O: 2 O: 2

The equation is balanced.

B. 2S + 3O₂ → 2SO₃

S: 2 S: 2
O: 6 O: 6

The equation is balanced.

C. Li + Cl₂ → LiCl

Li: 1 Li: 1
Cl: 2 Cl: 1

The equation is not balanced.

2Li + Cl₂ → 2LiCl

Li: 2 Li: 2
Cl: 2 Cl: 2

D: 2K + 2H₂O → H₂ + 2KOH

K: 2 K: 2
H: 4 H: 4
O: 2   O: 2

The equation is balanced.

E: 2Fe + Cu(NO₃)₂ → 2Cu + Fe(NO₃)₂

Fe: 2 Fe: 1
Cu: 1 Cu: 2
  N: 2 N: 2
O: 6 O: 6

The equation is not balanced.

2Fe + 2Cu(NO₃)₂ → 2Cu + 2Fe(NO₃)₂

Fe: 2 Fe: 2
Cu: 2 Cu: 2
N: 4 N: 4
O: 12   O: 12

The following equations that are balanced are A, B, and D.

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Be sure to answer all parts.The equilibrium constant, Kc, for the formation of nitrosyl chloride from nitric oxide and chlorine,

djverab [1.8K]

Answer: The reaction proceeds in the forward direction

Explanation:

For the given chemical equation:

$2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)$

Relation of $K_p\text{ with }K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta n_g}$

where,

$K_p$ = equilibrium constant in terms of partial pressure = ?

$K_c$ = equilibrium constant in terms of concentration = $6.5\times 10^4$

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = $35^oC=[35+273]K=308K$

$\Delta n_g$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-3=-1$

Putting values in above equation, we get:

$K_p=6.5\times 10^4\times (0.0821\times 500)^{-1}\\\\K_p=1583.43$

$K_p$ is the constant of a certain reaction at equilibrium while $Q_p$ is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

The expression of $Q_p$ for above equation follows:

$Q_p=\frac{(p_{NOCl})^2}{p_{Cl_2}\times (p_{NO})^2}$

We are given:

$p_{NOCl}=1.76atm$

$p_{NO}=1.01atm$

$p_{Cl_2}=0.42atm$

Putting values in above equation, we get:

$Q_p=\frac{(1.76)^2}{0.42\times (1.01)^2}=7.23$

We are given:

$K_p=1583.43$

There are 3 conditions:

When $K_{p}>Q_p$ ; the reaction is product favored.
When $K_{p}$ ; the reaction is reactant favored.
When $K_{p}=Q_p$ ; the reaction is in equilibrium

As, $K_p>Q_p$ , the reaction will be favoring product side.

Hence, the reaction proceeds in the forward direction

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3 years ago

Marcia is given an incomplete chemical equation that includes the number of nitrogen atoms present in the products of the reacti

Anna [14]

Answer: There would have to be three nitrogen atoms in the products. The law of conservation of matter states that the amount of substance before a reaction occurs should be the same as the amount of substance after the reaction.

Explanation: This is the EXACT sample answer from the test, just reword it if you want. ^

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3 years ago

Find the momentum of 5 kg bowling ball at 10 m/s.

leva [86]

30 kg m/s

momentum = mass x velocity = 10 x 3 m/s =30 kg m/s

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3 years ago

1-The chemical potential energy of bond A is greater than the chemical potential energy of bond B. Which statement best explains

Tju [1.3M]

It should be noted that bond A has greater energy because C. The atoms in bond A are held more tightly together than the atoms in bond B.

The relationship between the bond energies of nitrogen, iodine, and fluorine gases is that the bond in nitrogen gas is the most difficult to break.

From the information given, the molecule with the greatest bid energy is CH4. The bind energy measures the bond strength that the chemical bond has.

Also, the bond energy of the reactants in reaction 1 is greater than the bond energy of the reactants in reaction 2. Due to this, reaction 1 requires a greater input of energy than reaction 2.

Lastly, the difference in the bond energy of Chlorine and Bromine is that Bromine has more electron levels than chlorine.

Learn more about bonds on:

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6 0

3 years ago

Read 2 more answers

A lithium flame has a characteristic red color due to emissions of wavelength 671 nm. What is the mass equivalence of 1 mol of p

e-lub [12.9K]

Answer:

1.98x10⁻¹² kg

Explanation:

The energy of a photon is given by:

E= hc/λ

h is Planck's constant, 6.626x10⁻³⁴ J·s

c is the speed of light, 3x10⁸ m/s

and λ is the wavelenght, 671 nm (or 6.71x10⁻⁷m)

E = 6.626x10⁻³⁴ J·s * 3x10⁸ m/s ÷ 6.71x10⁻⁷m = 2.96x10⁻¹⁹ J

Now we multiply that value by Avogadro's number, to calculate the energy of 1 mol of such protons:

1 mol = 6.023x10²³ photons

2.96x10⁻¹⁹ J * 6.023x10²³ = 1.78x10⁵ J

Finally we calculate the mass equivalence using the equation:

E=m*c²

m=E/c²

m = 1.78x10⁵ J / (3x10⁸ m/s)² = 1.98x10⁻¹² kg

6 0

3 years ago