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lana [24]
3 years ago
12

Which consumers live in the open ocean?

Chemistry
2 answers:
Oksi-84 [34.3K]3 years ago
5 0
B. swordfish, dolphins, and sharks
mel-nik [20]3 years ago
3 0
<h2>Answer:</h2>

<u>The right option is B. swordfish, dolphins, and sharks </u>

<h2>Explanation:</h2>

Consumers have to feed on producers or other consumers to survive. They always prey to eat other animals or species of their own kind. They can also eat other species who interfere in their habitat. There are three types of consumers i.e primary, secondary and top predators. The top ones living off others in the sea which cause danger, one who puts to death other sea animals include swordfish, dolphins, and sharks.

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EASY Chemical reactions<br> Balance and classify
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76.0 mol of P4O10 contains how many moles of P?
NikAS [45]
For a mole of P4O10, there are 4 moles of P. Hence for 76 moles of P4O10, the number of P moles is a total of 304. 
8 0
3 years ago
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Your mass on the moon would be __________________________________ it is on the earth.
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Your weight would be less but your mass would remain the same.
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Reynolds number E. What is the mean velocity u. (ft/s) and the Reynolds number Re = pu., D/ for 35 gpm (gallons per minute) of w
Novay_Z [31]

Answer:

The mean velocity is 13 ft/s.

The Reynolds number is 88,583 and it is dimensionless.

Explanation:

We have water flowing in a pipe of 1.05 in diameter.

The density is ρ=62.3 lb/ft and the viscosity is 1.2 cP.

The mean velocity can be calculated as

u=\frac{Q}{A}=\frac{Q}{\pi*D^2/4}=\frac{35gpm }{3.14*(1.05in)^2/4}\\\\  u=\frac{35}{0.865}*\frac{gal}{min}\frac{1}{in^2}*\frac{231in^3}{1gal}*\frac{1}{60s} \\\\    u=156\,in/s=13\,ft/s

The Reynolds number now can be calculated for this flow as

Re=\frac{\rho*u*D}{\mu}

being ρ: density, u: mean velocity of the fluid, D: internal diameter of the pipe and μ the dynamic viscosity.

To simplify the calculation, we can first make all the variables have coherent units.

<em>Viscosity</em>

\mu=1.2cP=\frac{1.2}{100}\frac{g}{cm*s}*\frac{1lb}{453.6g}*\frac{30.48cm}{1ft}= 0.0008\frac{lb}{ft*s}

<em>Diameter</em>

D=1.05in*(\frac{1ft}{12in} )=0.0875ft

Then the Reynolds number is

Re=\frac{\rho*u*D}{\mu}\\\\Re=62.3\frac{lb}{ft^3}*13\frac{ft}{s} *0.0875ft*\frac{1}{0.0008}*\frac{ft*s}{lb}\\\\Re=88,583

8 0
3 years ago
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