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mash [69]
3 years ago
7

How do liquids with high velocity differ from liquids with low velocity

Chemistry
1 answer:
Yanka [14]3 years ago
5 0

Answer:

whah the other dude said :) also stay safe

Explanation:

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A latex balloon at sea level and room temperature (25°C) has a volume of 2.42 L. When the balloon is released by the child holdi
yarga [219]

Answer:

The answer to your question is: V2 = 1.94 l

Explanation:

Data

V1 = 2.42 l

T1 = 25°C

P1 = 1 atm

V2 = ?

T2 = 25 -11 = 14°C

P2 = 1(0.7) = 0.7 atm

Formula

P1V1/T1 = P2V2/T2

Clear V2 from the equation

V2 = P1V1T2/ P2T1

V2 = (1)((2.42)(14) / (0.7)(25)

V2 = 33.88 / 17.5

V2 = 1.94 l

6 0
3 years ago
8. How many atoms of cobalt are in a 0.39 mole sample of CoC
Debora [2.8K]

8.98

×

N

A

 

cobalt atoms

Explanation:

N

A

,

Avogadro's number

specifies  

6.0221

×

10

23

individual particles. It is simply another collective number like a dozen, or a score, or a gross.  

N

A

has the property that  

6.0221

×

10

23

individual cobalt atoms has a mass of  

58.93

⋅

g

. How did I know that? Did I have it memorized?

So the quantity is  

≈

 

54

×

10

23

cobalt atoms.

3 0
3 years ago
Help and explain step by step if you can!
Leona [35]

Answer:

the third one

Explanation:

if you look at it mathematically its the one that makes the most sense

4 0
3 years ago
The salt which in solution gives a pale green precipitate with sodium hydroxide solutionanda white precipitate with barium chlor
ELEN [110]

Answer:

Analytical Chemistry. The salt which in solution gives a pale green precipitate with sodium hydroxide solution and a white precipitate with barium chloride solution is : Iron (III) sulphate.

7 0
2 years ago
Read 2 more answers
Using the van der Waals equation, determine the pressure of 500.0 g of SO2(g) in a 6.30-L vessel at 633 K. For SO2(g), a = 6.865
dem82 [27]

Answer:

The pressure is 58.75 atm.

Explanation:

From Vanderwaal's equation,

P = nRT/(V-nb) - n^2a/V^2

n is the number of moles of SO2 = mass/MW = 500/64 = 7.81 mol

R is gas constant = 0.0821 L.atm/mol.K

T is temperature of the vessel = 633 K

V is volume of the vessel = 6.3 L

a & b are Vanderwaal's constant = 6.865 L^2.atm/mol^2 and 0.0567 L/mol respectively.

P = (7.81×0.0821×633)/(6.3 - 7.81×0.05679) - (7.81^2 × 6.865)/6.3^2 = 69.30 - 10.55 = 58.75 atm

4 0
3 years ago
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