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Archy [21]
3 years ago
12

When the temperature of the air is 50°C, the velocity of a sound wave traveling through the air is approximately?

Physics
2 answers:
noname [10]3 years ago
5 0

The answer is:

C. 361 m/s

The explanation:

To calculate  the speed of sound at a given temperature (50°C) we are going to use this formula:

v = 331 + 0.6T

when V is the velocity

and T is the temperature = 50°C

by substitution:

v = 331 + 0.6(50)

v = 361 m/s

So, The correct answer is C.

because of the variation of the motion of the molecules of air with change of temperature so, the velocity (V) of the  sound in the air is change with temperature.

Blababa [14]3 years ago
5 0
<span>When the temperature of the air is 50°C, the velocity of a sound wave traveling through the air is approximately Answer</span><span>: 361 m/s</span>
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You place a 55.0 kg box on a track that makes an angle of 28.0 degrees with the horizontal. The coefficient of static friction b
Radda [10]

Answer:

\theta=34 \textdegree

Explanation:

From the question we are told that:

Mass m=55kg

Angle \theta =28.0

Coefficient of static friction \alpha =0.680

Generally, the equation for Newtons second Law is mathematically given by

For

\sum_y=0

N=mgcos \theta

for

\sum_x=0

F_{s}=mgsin\theta

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F_{s}=\alpha*N\\\\F_{s}=\alpha*m*gcos \theta

F_{s}=0.68*55*9.8*cos 28

F_{s}=323.62N

Therefore

\alpha mgcos \theta=mg sin \theta

\theta=tan^{-1}(0.68)

\theta=34 \textdegree

6 0
2 years ago
A ball is rolling down a hill. Wich action would slow the ball down?
Feliz [49]

Answer:

Friction Force

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Explanation:

4 0
2 years ago
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What is one way that light waves differ from sound waves?(1 point)
Shalnov [3]
Light waves are transverse while sound waves are longitudinal. Light waves can travel in vacuum. Sound waves require a material medium to travel, and hence, cannot travel in vacuum. The speed of light in a medium is constant.

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7 0
1 year ago
An insulated piston–cylinder device contains 100 L of air at 400 kPa and 25°C. A paddle wheel within the cylinder is rotated unt
solong [7]

Answer:

T'=70.92°C

Explanation:

Given that

V= 100 L=0.1 m³

P=400 KPa

T=25°C

Work done on the air = 15 KJ

W= -15 KJ

If we assume that air is ideal gas

P V = m R T

R=0.287 KJ/kg.K for air

T= 273 + 25 = 298 K

By putting the values

P V = m R T

400 x 0.1 = m x 0.287 x 298

m=0.46 kg

From first law of thermodynamics

Q= ΔU +W

Insulated piston–cylinder  , Q=0

ΔU  = m Cv  ΔT

   ΔU = - W

Cv = 0.71 KJ/kg.k for air

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T'=70.92 °C

So the final temperature of air is T'=70.92 °C

7 0
3 years ago
An object experiences an acceleration of -6.8m/s^2. As a result, it accelerates from 54m/s to a complete stop. how much distance
Kipish [7]

Answer:

210 m

Explanation:

Given:

a = -6.8 m/s²

v₀ = 54 m/s

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Δx ≈ 210 m

6 0
3 years ago
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