A train is rounding a circular curve whose radius is 2.55 x 102 m. At one instant, the train has an angular acceleration of 1.48
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Answer:
Time period of oscillation on moon will be equal to 3.347 sec
Explanation:
We have given mass which is attached to the spring m = 3.42 kg
Spring constant K = 12 N/m
We have to find the period of oscillation
Period of oscillation is equal to , here m is mass and K is spring constant
So period of oscillation
So time period of oscillation will be equal to 3.347 sec
As it is a spring mass system and from the relation we can see that time period is independent of g
So time period will be same on earth and moon