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abruzzese [7]
3 years ago
7

A train is rounding a circular curve whose radius is 2.55 x 102 m. At one instant, the train has an angular acceleration of 1.48

x 10-3 rad/s2 and an angular speed of 0.0553 rad/s. (a) Find the magnitude of the total acceleration (centripetal plus tangential) of the train. (b) Determine the angle of the total acceleration relative to the radial direction.
Physics
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

B

Explanation:

determine and acceleration

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A ray of light is moving from a material having a high indexof refraction into a material with a lower index of refraction.
luda_lava [24]

(a) Away from the normal

We can find the direction of bending of the ray of light by using Snell's equation:

n_1 sin \theta_1 = n_2 sin \theta_2

where we have:

n1, n2: index of refraction of the first and second medium

\theta_1, \theta_2; angle that the incident and the refracted ray form with the normal to the surface

Here, the light ray moves from a material with high index of refraction to a material with lower index, so we have

n_1 > n_2

Re-arranging Snell's law we find

sin \theta_2 = \frac{n_1}{n_2} sin \theta_1

since we have

\frac{n_1}{n_2}>1

this implies

sin \theta_2 > sin \theta_1\\\theta_2 > \theta_1

so the ray of light bends away from the normal.

(b) The wavelength is greater in the second material (the one with lower index of refraction)

The wavelength of the light in a medium is given by

\lambda=\frac{\lambda_0}{n}

where

\lambda_0 is the wavelength of the light in a vacuum

n is the refractive index

The equation can be rewritten as

\lambda_0 = \lambda_1 n_1 = \lambda_2 n_2

and again it can be rewritten as

\lambda_2 = \frac{n_1}{n_2} \lambda_1

where

\lambda_1 = 600 nm\\\frac{n_1}{n_2}>1

Therefore, we have that the wavelength in the second medium (the one with lower index of refraction) is longer than the wavelength in the first medium.

(c) The frequency remains the same

Wavelength and speed of a light ray depend on the medium in which the wave is travelling through, however the frequency does not depend on that, so it remains the same in the two mediums.

8 0
3 years ago
The construction of a flat rectangular roof (6.17 m × 5.92 m) allows it to withstand a maximum net outward force of 2.00 × 104 N
Blababa [14]

Answer:

v_2=29.13\ m/s

Explanation:

It is given that,

Dimension of the rectangular roof, (6.17 m × 5.92 m)

The maximum net outward force, F=2\times 10^4\ N

The density of air, \rho=1.29\ kg/m^3

The Bernoulli equation is used to find wind speed of this roof blow outward. It is given by :

P_1+\dfrac{1}{2}\rho v_1^2=P_2+\dfrac{1}{2}\rho v_2^2

Here, v_1=0 (since air inside the roof is not moving)

v_2=\sqrt{\dfrac{2(P_1-P_2)}{\rho}}

Since, F=(P_1-P_2)A

v_2=\sqrt{\dfrac{2F}{\rho A}}

v_2=\sqrt{\dfrac{2\times 2\times 10^4}{1.29\times 6.17\times 5.92 }}

v_2=29.13\ m/s

So, the wind speed of  this roof blow outward is 29.13 m/s. Hence, this is the required solution.

5 0
4 years ago
Ysical Science A
lisov135 [29]
Answer:
4.5 Cm
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3 years ago
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Which of the following best describes chemical weathering?
aliina [53]
D. A chemical process that changes the composition of rocks, causing them to break down
7 0
3 years ago
2. This diagram represents a top-down view of an experiment on a table. The 250 g and 100 g masses are falling and are pulling t
Rasek [7]

Answer:

According to the data given in the question, experiment on table two pulling and falling masses are arranged in the fig. 250  g is pulling right side and   100 g pulling down. The gravitational force is common to both the masses, so we cannot say that the block moves towards heavier mass, also the block  does not move towards the lighter mass.

Obviously, the effect of heavier mass of 250 g is more on the block, so the block moves towards right bottom corner. i.e., diagonally between two masses


please find the attachment.

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3 years ago
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