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Aleksandr [31]
3 years ago
10

If ax2 + bx + c = 0 then

Mathematics
1 answer:
Alexeev081 [22]3 years ago
4 0
3x² + 10x + 6 = 0
x = -(10) ± √((10)² - 4(3)(6))
                       2(3)
x = -10 ± √(100 - 72)
                   6
x = -10 ± √(28)
              6
x = -10 ± 2√(7)
              6
x = -5 ± √(7)
           3
x = -1²/₃ ± ¹/₃√(7)






5x² - 6x + 1 = 0
x = -(-6) ± √((-6)² - 4(5)(1))
                     2(5)
x = 6 ± √(36 - 20)
               10
x = 6 ± √(16)
          10
x = 6 ± 4
        10
x = 3 ± 2
         5
x = 3 + 2    or    x = 3 - 2
         5                       5
x = 5    or    x = -1
      5                  5
x = 1    or    x = -0.2






2x² - 7x - 15 = 0
x = -(-7) ± √((-7)² - 4(2)(-15))
                       2(2)
x = 7 ± √(49 + 120)
                 4
x = 7 ± √(169)
             4
x = 7 ± 13
          4
x = 7 + 13    or    x = 7 - 13
          4                         4
x = 20    or    x = 6
       4                  4
x = 5    or    x = 1.5






x² + 4x + 1 = 0
x = -(4) ± √((4)² - 4(1)(1))
                   2(1)
x = -4 ± √(16 - 4)
                2
x = -4 ± √(12)
             2
x = -4 ± 2√(3)
             2
x = -2 ± √(3)
           2
x = -1 ± ¹/₂√(3)
x = -1 + ¹/₂√(3)    or    x = -1 - ¹/₂√(3)
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R560 invested at 8% p.a. simple interest for 3 years​
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Answer:

R 694.4

Explanation:

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the area of a circle is 81 pi m^2. what is the circumference, in meters? express your answer in terms of pi.
mestny [16]
<h3>Answer:    18pi</h3>

============================================================

Explanation:

The area 81pi square meters leads to the radius 9 meters

Use the formula A = pi*r^2 to see why this is the case. You plug in A = 81pi and solve for r to get r = 9.

-----------------

Once you know the radius, you can determine the circumference C

C = 2*pi*r

C = 2*pi*9

C = 2*9*pi

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8 0
3 years ago
Y^3-9y^2+y-9 I don't know how to solve this can you help
aleksley [76]
I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?

In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0    and    (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.

So you're final answer should be y = i and 9
3 0
3 years ago
Jada bought 3 shirts that cost $19.99 each before discount. What was her total after the discount? The percentage discount at a
Alex777 [14]
Total after the discount would be $77.96
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