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3 years ago

Which statement describes compounds?

Chemistry

2 answers:

sveta [45]3 years ago

8 0

Compounds are represented by chemical formulas

noname [10]3 years ago

7 0

Answer:

The correct answer is "Compounds are represented by chemical formulas. "

Explanation:

A chemical formula is a graphic expression of the elements that make up any chemical compound, as well as the numbers and proportions of their respective atoms.

That is, the chemical formulas are made up of chemical symbols that indicate the elements that make up a compound and the number of atoms that each element contributes contains the formula. The latter is indicated by a subscript, that is, a small number that is placed below and to the right of each element that requires it.

Then, the correct answer is "Compounds are represented by chemical formulas. "

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Oxygen has 6 valence electrons. How many electrons does an atom of oxygen need to become stable?

SOVA2 [1]

Answer:

Two electrons

Explanation:

According to the octet rule, atoms must bond to each other, sharing electrons among themselves in an attempt to complete their valence shell (last layer of the electrosphere). In other words, an atom becomes stable when it has 8 electrons in its valence shell.

Oxygen atoms have six electrons in their valence shell, so to achieve the stability suggested by the octet rule (eight electrons), these atoms share two electrons, forming one oxygen gas (O₂) molecule.

8 0

4 years ago

Read 2 more answers

elixir [45]

Answer:

no le entiendo pero si me se la respuesta ya tu sabe ✨✨✨✨

7 0

3 years ago

Enter your answer in the provided box.S(rhombic) + O2(g) → SO2(g) ΔHo rxn= −296.06 kJ/molS(monoclinic) + O2(g) → SO2(g) ΔHo rxn=

IgorC [24]

Answer: $\Delta H^0=+0.3kJ/mol$ .

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

$S_{rhombic}+O_2(g)\rightarrow SO_2(g)$ $\Delta H^0_1=-296.06kJ$ (1)

$S_{monoclinic}+O_2(g)\rightarrow SO_2(g)/tex] [tex]\Delta H^0_2=-296.36kJ$ (2)

The final reaction is:

$S_{rhombic}\rightarrow S_{monoclinic}$ $\Delta H^0_3=?$ (3)

By subtracting (1) and (2)

$\Delta H^0_3=\Delta H^0_1-\Delta H^0_2=-296.06kJ-(-296.36kJ)=0.3kJ$

Hence the enthalpy change for the transformation S(rhombic) → S(monoclinic) is 0.3kJ

3 0

3 years ago

In the reaction between bromine and sodium, a bromine atom gains an electron. What ion is formed? Is the bromine oxidized, or is

SVETLANKA909090 [29]

Answer: The ion formed after the reduction of bromine is $Br^-$

Explanation:

The electronic configuration of Sodium (Na) = $[Ne]3s^1$

The electronic configuration of Bromine (Br) = $[Ar]3d^{10}4s^24p^5$

From the above configurations, Sodium ion will loose 1 electron in order to gain stable electronic configuration and that electron is accepted by the Bromine atom because it is 1 electron short of the stable electronic configuration.

$Na\rightarrow Na^++e^-$ (oxidation reaction)