Which statement describes compounds?
2 answers:
You might be interested in
Hello!
First, we need to determine the pKa of the base. It can be found applying the following equation:
Now, we can apply the Henderson-Hasselbach's equation in the following way:
![pH=pKa+log( \frac{[CH_3NH_2]}{[CH_3NH_3Cl]} )=10,65+log( \frac{0,18M}{0,73M} )=10,04](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%20%5Cfrac%7B%5BCH_3NH_2%5D%7D%7B%5BCH_3NH_3Cl%5D%7D%20%29%3D10%2C65%2Blog%28%20%5Cfrac%7B0%2C18M%7D%7B0%2C73M%7D%20%29%3D10%2C04)
So, the pH of this buffer solution is 10,04
Have a nice day!
First, we need to determine the pKa of the base. It can be found applying the following equation:
Now, we can apply the Henderson-Hasselbach's equation in the following way:
So, the pH of this buffer solution is 10,04
Have a nice day!
Answer:
E.F= OH
M.F=
Explanation:
Empirical Formula
Step 1: Calculate mols of each element
0.44gH(1 mol H/ 1.008g H)= 0.4365 mol H
*note leave extra sig figs for calculations
6.92gO(1 mol O/ 16 g O)=0.4325 mol O
Step 2: Identify which is the smallest mol
*in this case 0.4365 mol H> 0.4325 mol O so we will use 0.4325 mol O
Step 3: Divide above calculations by the smallest mol
0.4325 mol O/0.4325= 1
0.4365 mol H/0.4325= 1.009 *rounds to 1
Step 4: use calculations as subscripts
Oxygen = 1 so the subscript will 1 (O)
Hydrogen = 1 so the subscript will 1 (H)
making E.F= OH
Molecular Formula:
Step 1: identify molecular mass and mass from the E.F
the molecular mass is given 34.00g/mol
the mass of the E.F is
(oxygen mass from periodic table)+(hydrogen mass from periodic table)
16+1.008= 17.008
Step 2:Divide the molecular mass by the mass given by the emipirical formula.
round to 2
Step 3:Multiply the empirical formula (the subscripts) by this number to get the molecular formula. ANSWER: M.F=2(OH)-