Ask question

Ask question

All categories

3 years ago

6

if an object is moving at a constant speed, the forces acting on it must be ___. Another way to say this is that the net force =

__.

1 answer:

Umnica [9.8K]3 years ago

3 0

Answer : <u> Equal</u>, <u>Zero</u>

If the object is moving at constant speed, it is under "equilibrium". So, forces acting on object are equal and the net force is zero.

You might be interested in

An infinite plane lies in the yz-plane and it has a uniform surface charge density.

Allisa [31]

Answer:

<u>So the correct answer is letter e)</u>

Explanation:

The electric field of an infinite yz-plane with a uniform surface charge density (σ) is given by:

$E=\frac{\sigma }{2\epsilon_{0}}$

Where ε₀ is the electric permitivity.

<u>As we see, this electric field does not depend on distance, so the correct answer is letter e)</u>

I hope it helps you!

6 0

3 years ago

Can an object have a positive position, but a negative velocity? Explain your reasoning.

photoshop1234 [79]

Answer:

Yes

Explanation:

A position describes the position of an object relative to the x/y-axis (or the four cardinal directions). A velocity is a vector quantity, defining speed with direction.

So if an object is in a positive position, it means they are in the positive x-axis direction (or wherever on the scale the positive values are stated to be) and if it has a negative velocity, it means said object is moving in the opposite direction of the positive x-axis. It is possible for the object to still be in the positive position as it's moving with a negative velocity

4 0

3 years ago

Suppose a 1 Gbps point-to-point link is being set up between the Earth and a new lunar colony. The distance from the moon to Ear

vagabundo [1.1K]

Answer:

The time required to send the data from Earth to Moon will be 1.28s while for a two way communication, to send it back to the earth, it will take double time i.e. <em>RTT = 2.56s </em>

Explanation:

Distance between Earth and Moon = 385,000 km = 3.85 x 10⁸m

Speed of data travel = speed of light ≈ 3 x 10⁸m/s

As, v=d/t

t=d/v

$t=\frac{3.85*10^{8} }{3*10^{8}}$

t=1.28s

RTT = Double of single way time taken = 2x1.28

<em><u>RTT=2.56s</u></em>

7 0

3 years ago

Explain how longitudinal waves and transverse waves are similar to each other and different from each other.

VashaNatasha [74]

Similar:
-
For transverse waves, the waves move in perpendicular direction to the source of vibration.
For longitudinal waves, the waves move in parallel direction to the source of vibration .
They are similar in the sense that energy is transferred in the form of waves.
-
Difference:
-
Transverse Waves: Displacement of the medium is perpendicular to the direction of propagation of the wave.
Longitudinal Waves: Displacement of the medium is parallel to the direction of propagation of the wave.

3 0

3 years ago

Two identical balls each have a mass of 35.0 grams and a charge of . The balls are released from rest when they are separated by

OlgaM077 [116]

The given question is incomplete. The complete question is as follows.

Two identical balls each have a mass of 35.0 grams and a charge of q = 3.50 \times 10^{-6}C[/tex]. The balls are released from rest when they are separated by a distance of 6.00 cm. What is the speed of each ball when the distance between them has tripled? Use k = $9.00 \times 10^{9} Nm^{2}/C^{2}$ .

Explanation:

According to the conservation of energy, the formula will be as follows.

$\frac{kq_{1}q_{2}}{r_{1}} = \frac{kq_{1}q_{2}}{(3r_{1})} + \frac{1}{2}mv^{2} + \frac{1}{2}mv^{2}$

or, $\frac{kq_{1}q_{2}}{r_{1}}[1 - \frac{1}{3}] = mv^{2}$

Putting the given values into the above formula as follows.

$\frac{kq_{1}q_{2}}{r_{1}}[1 - \frac{1}{3}] = mv^{2}$

$\frac{9 \times 10^{9} \times (3.5 \times 10^{-6})^{2}}{0.09} \times \frac{2}{3} = \frac{35}{1000}v^{2}$

$v^{2}$ = 23.333

v = 4.83 m/s

Thus, we can conclude that speed of each ball when the distance between them has tripled is 4.83 m/s.

7 0

4 years ago