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2 years ago

For the hypothetical compound AX3, which statement is true?

Chemistry

1 answer:

Artist 52 [7]2 years ago

5 0

Answer:

b because it says it in the question

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Water molecules are positive on one end, negative on the other. Predict what a negatively charged balloon will do when placed cl

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Answer: The water (in a subtle sort of way) will now be attracted towards the balloon

I attached a picture to help make sense

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2 years ago

How long would it take a car to travel a distance of 260 kilometers if it were traveling at 65 km/hour

Mariulka [41]

Answer:

4 answers

Explanation:

Do simple divison

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3 years ago

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If someone adds million of small fish to a lake, how would the number of big fish change

Molodets [167]

The population of big fish would increase because they have more food

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3 years ago

What is the precent yield if the actual yield is 25g and 100g should have formed?

11Alexandr11 [23.1K]

Answer:

Percent yield is 25%

Explanation:

Information given is

Actual yield is 25 g

But the yield should be 100 g

The percent yield is defined as the ratio of the actual yield and the predicted yield it means that out of the predicted yield what percentage of the actual yield is obtained

∴ Percent yield = (Actual yield ÷ Predicted yield) × 100

In case of the given problem the percent yield will be

(25÷100) × 100 = 25%

∴ Percent yield = 25%

3 0

3 years ago

: If a 250. mL sample of the above buffer solution initially has 0.0800 mol H2C6H5O7 - and 0.0600 mol HC6H5O7 2- , what would be

Jet001 [13]

Answer: New concentration of $HC_{6}H_{5}O^{2-}_{7}$ is 0.23 M.

Explanation:

The given data is as follows.

Moles of $HC_{6}H_{5}O^{2-}_{7}$ = 0.06 mol

Moles of $H_{2}C_{6}H_{5}O_{7}$ = 0.08 mol

Therefore, moles of $OH^{-}$ added are as follows.

Moles of $OH^{-}$ = $0.125 \times \frac{25}{1000}$

= 0.003125 mol

Now, new moles of $HC_{6}H_{5}O^{2-}_{7}$ = 0.06 + 0.003125

= 0.063125

Therefore, new concentration of $HC_{6}H_{5}O^{2-}_{7}$ will be calculated as follows.

Concentration = $\frac{0.063125}{0.275}$

= 0.23 M

Thus, we can conclude that new concentration of $HC_{6}H_{5}O^{2-}_{7}$ is 0.23 M.

4 0

3 years ago