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Mazyrski [523]
2 years ago
6

A ______ is a process in which the physical and chemical properties of the original substances change as new substances are form

ed.
fill in the blank with the answer.
Chemistry
2 answers:
Jlenok [28]2 years ago
7 0

Answer:

chemical change

Explanation:

In chemical change , considerable amount of heat is used , hence a change in substance formed

kondaur [170]2 years ago
6 0
Chemical change - Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances.
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What type of chest tube system does this statement describe?
Komok [63]

Answer:

<em>Dry suction chest tube system</em>

Explanation:

<em>The dry suction drains that are self-regulating today use a small, adjustable regulator installed into the drain. </em>

So long as there is enough air flow from the suction of the wall (that will be shown on the drain) it will respond correctly to changes in the pressure of the source or the patient to retain suction at the drain level.

It's also a quiet mode of activity.

4 0
3 years ago
What distinguishes a chemical property from a physical property?
Dvinal [7]
C. Chemical properties always change depending on temperature or pressure
6 0
3 years ago
Read 2 more answers
Determine the theoretical yield and the percent yield if 21.8 g of K2CO3 is produced from reacting 27.9 g KO2 with 57.0 g CO2. T
Alex_Xolod [135]

Answer:

26.9 g

81%

Explanation:

The equation of the reaction is;

4 KO2(s) + 2 CO2(g) → 3 O2(g) + 2 K2CO3(s)

Number of moles of KO2= 27.9g/71.1 g/mol = 0.39 moles

4 moles of KO2 yields 2 moles of K2CO3

0.39 moles of KO2 yields 0.39 × 2/4 = 0.195 moles of K2CO3

Number of moles of CO2 = 57g/ 44.01 g/mol = 1.295 moles

2 moles of CO2 yields 2 moles of K2CO3

1.295 moles of CO2 yields 1.295 × 2/2 = 1.295 moles of K2CO3

Hence the limiting reactant is KO2

Theoretical yield = 0.195 moles of K2CO3 × 138.205 g/mol = 26.9 g

Percent yield = actual yield/theoretical yield × 100

Percent yield = 21.8/26.9 × 100

Percent yield = 81%

5 0
3 years ago
If a 45.6 g piece of aluminum has a density of 2.1 g/mL, what volume would it have?
Mashcka [7]

Answer:

\boxed {\tt 21.7142857 \ mL}

Explanation:

The density formula is:

d=\frac{m}{v}

Rearrange this formula for v, volume. Multiply by v, then divide by d.

d*v=\frac{m}{v}

d*v=m

\frac{d*v}{d} =\frac{m}{d}

v=\frac{m}{d}

Volume can be found by dividing the mass by the density. The mass of the aluminum is 45.6 grams and the density is 2.1 grams per milliliter.

v=\frac{45.6 \ g }{ 2.1 \ g/mL}

Divide. Note the grams, or g, will cancel out.

v=\frac{45.6 }{2.1 \ g}

v= 21.7142857 \ mL

The volume of the aluminum is 21.7142857 milliliters.

3 0
3 years ago
How many fluorine atoms are in 750.0 mL of a 0.500M HF solution?
SIZIF [17.4K]

Answer:

2.26 \times 10^{23}atomsF

Explanation:

Step 1: Given data

  • Molarity of the HF solution (M): 0.500 M
  • Volume of the solution (V): 750.0 mL

Step 2: Convert "V" to liters

We will use the conversion factor 1 L = 1000 mL.

750.0 mL × 1 L/1000 mL = 0.7500 L

Step 3: Calculate the moles of HF

We will use the following expression.

n = M × V

n = 0.500 mol/L × 0.7500 L = 0.375 mol

Step 4: Calculate the atoms of F in 0.375 moles of HF

We will use the following relationships:

  • 1 mole of HF contains 1 mole of atoms of F.
  • 1 mole of atoms of F contains 6.02 × 10²³ atoms of F (Avogadro's number).

0.375 mol HF \times \frac{1 mol F}{1 molHF} \times \frac{6.02 \times 10^{23}atomsF }{1 mol F} = 2.26 \times 10^{23}atomsF

7 0
3 years ago
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