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Answer:
ΔH = -45.1872 kJ , where negative sign signifies heat loss.
Q = ΔH = -45.1872 kJ , where negative sign signifies heat loss.
S system = -0.141 kJ/K
S surroundings = 0.1536 kJ/K
S universe = -0.141 kJ/K + 0.1536 kJ/K = 0.0126 kJ/K
Explanation:
Given:
Cp = 4. 184 J/(mole. K)
T₁ = 75 ⁰C
T₂ = 21 ⁰C
Mass of water = 200 g = 0.2 kg
Since,
ΔH = 0.2*4.184*(21-75) kJ
<u> ΔH = -45.1872 kJ , where negative sign signifies heat loss.</u>
Since the process is at constant pressure
<u> Q = ΔH = -45.1872 kJ , where negative sign signifies heat loss.</u>
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
T₁ = 75 ⁰C = 348 .15 K
T₂ = 21 ⁰C = 294.15 K
The entropy of the water is given by:
<u> S = m×Cp×ln(T₂ /T₁) </u>
S = 0.2*4.184*ln(294.15/348.15)
<u> S system = -0.141 kJ/K</u>
The heat gain by surroundings
<u> dQ = -Qreaction = 45.1872 kJ </u>
The entropy change of surroundings is
S surr = dQ/T₂ = 45.1872/294 .15
<u> S surr = 0.1536 kJ/K </u>
The entropy of universe is the sum total of the entropy of the system and the surroundings and thus,
S universe = Ssys + Ssurr
<u> S universe = -0.141 kJ/K + 0.1536 kJ/K = 0.0126 kJ/K</u>
Answer:
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Answer:
Explanation:
There is no external force applied, therefore there is a moment's preservation throughout the trajectory.
<em>Initial momentum = Final momentum. </em>
The total mass is equal to
Where,
mass of ship
mass of fuell expeled.
As the moment is conserved we have,
Where,
Velocity of fuel
Velocity of Space Ship
Solving and re-arrange to we have,
Where c is the speed of light.
Therefore the ship be moving with speed