Answer: 0.62
Explanation:
Coefficient of friction is defined as the ratio of the moving force (Fm) acting on a body to the normal reaction (R).
Note that the normal reaction acts vertically on the object and is equal to the objects weight (W) i.e W=R
Since W = mg, W = 38.4 ×10
W= 384N =R
Normal reaction = 384N
The horizontal force acting on the body will be the moving force which is 238N
Coefficient of friction = Fm/R
Coefficient of friction = 238/384
Coefficient of friction = 0.62
Therefore, coefficient of kinetic friction between the box and the floor is 0.62
Answer:
Explanation:
spring constant k = 425 N/m
a ) At the point of equilibrium
restoring force = frictional force
= kx = 10 N
425 x = 10
x = 2.35 cm
b )
Work done by frictional force
= -10 x 2.35 x 10⁻² x 2 J ( Distance is twice of 2.35 cm )
= - 0.47 J
= Kinetic energy remaining with the cookie as it slides back through the position where the spring is unstretched .
= 425 - 0.47
= 424.53 J
=
Using idea of conservation of impulse-momentum theorem, the instantaneous velocity times mass is equal to force times the change in time.
mv = Ft
To reduce the force, decrease the velocity and mass. You can also extend the time of the collision. This is why cars collapse on impact. They were design that way to reduce the force on the car and the passenger.
Hopes this helps!
There's not enough information given to do that calculation.
-- The question doesn't specify whether the satellite is on the
shelf in the Vehicle Assembly Building before being installed
onto the booster, or inside the nose-cone as the rocket is slowly
being rolled to the launch-pad, or on its ascent to orbit after launch,
or in orbit. Its velocity in each of these situations is different.
-- The question reveals only the satellite's mass, but the answer
doesn't depend on that number. The satellite's velocity depends
on the speed of the truck or the rocket carrying it, or the size of
the orbit it's in. The question doesn't give any of these.
==> In particular, the size of a satellite's orbit, or its speed in that
orbit, DO NOT depend on its mass.
For example:
There are hundreds of TV satellites ... the ones that match the
Earth's rotation and appear motionless in the sky. They have
many different sizes, shapes, and masses, but they're all in the
same geostationary orbit, 22,000 miles above the equator, and
they all have the same average orbital velocity, zero displacement
per (23 hours 56 minutes 4 seconds).
