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Ilya [14]
3 years ago
12

When communicating with Apollo astronauts, scientists on Earth use radio waves and the "over to you" method of communication. Th

is method must be used because of the delay in communication. This delay is due to the A) scattering of electromagnetic waves in space. Eliminate B) fact that sound waves do not travel in a vacuum. C) poor reflective nature of the surface of the moon. D) distance to the moon and the speed of electromagnetic waves.
Chemistry
1 answer:
Dominik [7]3 years ago
6 0

The answer is; D

While electromagnetic waves travel at an astounding 3.00 x 10^8 m/s and any delay seems imperceptible in short distances, in long distances, the waves take some time to reach the other end. This is why there is usually a small delay when ground communication tries to reach astronauts in space.  Also, remember that when a communication is relayed from the earth, it has to reach the destination and then wait for a response back to earth which covers the same distance or longer/shorter if the target is moving.

The distance to the moon is 384,400 km, therefore multiply this by 2 = 768,800 km

768,800,000m/300,000,000m = 2. 56 seconds

Therefore radio waves sent to the moon from earth will have a minimum  2.5  seconds delay not considering the processing time of this communication by the destination before sending feedback.  ‘Over to you’ signals end of a message by the messenger hence allowing the other messenger on the other to respond.  


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4 0
4 years ago
Read 2 more answers
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.02 g of ethane is
miv72 [106K]

Answer:

3.13g

Explanation:

First, we'll begin by writing a balanced equation between the reaction of gaseous ethane with gaseous oxygen to produce gaseous carbon dioxide and gaseous water. This is illustrated below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Next, let us calculate the mass of C2H6 and the mass of O2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of C2H6 = (12x2) + (6x1) = 24 + 6 = 30g/mol

The mass of C2H6 that reacted from the balanced equation = 2 x 30 = 60g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 that reacted from the balanced equation = 7 x 32 = 224g

Now, to calculate the left over mass of ethane (C2H6), let us first calculate the mass of ethane (C2H6) that will react with 22g of oxygen(O2). This can be achieved by doing the following:

From the balanced equation above,

60g of C2H6 reacted with 224g of O2.

Therefore, Xg of C2H6 will react with 22g of O2 i.e

Xg of C2H6 = (60 x 22)/224

Xg of C2H6 = 5.89g

From the calculations above, 5.89g will react completely with 22g of O2.

The left over mass of C2H6 can be obtained as follow:

Mass of C2H6 from the question = 9.02g

Mass of C2H6 that reacted = 5.89g

The left over mass of C2H6 =?

The left over mass of C2H6 = Mass of C2H6 - mass of C2H6 that reacted

Left over mass of C2H6 = 9.02 - 5.89

Left over mass of C2H6 = 3.13g

7 0
4 years ago
4. You have a 1 M solution of KCl. You need to generate 100 mL of 0.25 M KCl. Explain how you would make this
andrew-mc [135]

1M KCl will require 25 mL to generate 100 mL of 0.25M KCl.

Molarity of a solution is defined as number of moles of solute present in 1000 mL of the solution.

M=\frac{n}{V}\times1000

So molarity is inversely proportional to the volume of the solution.

As solution is diluted. Molarity of the solution decreases.

1M of KCl means 1 mole of KCl in 1000 mL of the solution.

1M KCl is four times as concentrated as 0.25M KCl.

Therefore, to make 100 mL of 0.25M will require \frac{100}{4}= 25 mL of 1M KCl diluted to 100 mL of distilled water.

Easy alternative: Dilution formula

M_1\times V_1 = M_2\times V_2

Where M_1 \,and\, V_1 are volume and concentration of first solution

and M_2\,and\, V_2 are of second solution.

1\times V= 0.25\times100\\\\V= 25\,mL

Learn more about dilution formula here,

brainly.com/question/18917740

#SPJ4

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