Answer:
ar = 5.86*10^-3 m/s^2
Explanation:
In order to calculate the radial acceleration of the Earth, you first take into account the linear speed of the Earth in its orbit.
You use the following formula:
(1)
G: Cavendish's constant = 6.67*10^-11 m^3 kg^-1 s^-2
Ms: Sun's mass = 1.98*10^30 kg
r: distance between Sun ad Earth = 1.50*10^8 km = 1.50*10^11 m
Furthermore, you take into account that the radial acceleration is given by:
(2)
You replace the equation (1) into the equation (2) and replace the values of all parameters:

The radial acceleration of the Earth, towards the sun is 5.86*10^-3 m/s^2
A falling raindrop.
The reason why it's because mass of a raindrop is under influence of gravity pushing it down towards earth surface. When it hit the surface kinetic energy is released.
The hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, will be s = 9.5 m.
The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.
These equations link five kinematic variables:
Displacement (denoted by Δx)
Initial Velocity v0
Final Velocity denoted by v
Time interval (denoted by t)
Constant acceleration (denoted by a)
These equations define motion at either constant velocity or at constant acceleration. Because kinematics equations are only applicable at a constant acceleration or a constant speed, we cannot use them if either of the two is changing.
v = u + at
0 = 9.5 + a (2)
a = - 9.5 /2 m/
=
+ 2as
0 =
+ 2* (- 9.5 /2) * s
-
= - 9.5 s
s = 9.5 m
To learn more about kinematics here
brainly.com/question/27126557
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