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Greeley [361]
3 years ago
6

Allen is carrying out reactions in a lab. One of the products in all reactions is found to be either a precipitate, a gas, or wa

ter. What is common between all these reactions?
Chemistry
2 answers:
juin [17]3 years ago
4 0

Answer:

Decomposition reaction.

Explanation:

There is formation of a precipitate or evolution of gas or formation of water generally during decomposition reactions.

They involve breaking of a compound into two or more new compounds or one or more element.

Example:

Decomposition of calcium carbonate.

CaCO_{3}--->CaO(s)+CO_{2}(g)

H_{2}SO_{3}--->H_{2}O+SO_{2}(g)

Artist 52 [7]3 years ago
3 0
All decomposition reactions. 
Hope this helps!(: 
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5.0 x 10^24 molecules equal
Ratling [72]
<span>4.999999999999999e</span>+<span>24 this is what i got on the calculator but i dont know if its right.</span>
8 0
3 years ago
What should iron oxide be categorized
11111nata11111 [884]

Answer:

What are you doing stepbro?

Explanation:

5 0
3 years ago
Read 2 more answers
Calculate the total energy, in kilojoules, that is needed to turn a 46 g block
neonofarm [45]

Answer: The total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.

Explanation:

Given: Mass = 46 g

Initial temperature = -25^{o}C

Final temperature = 100^{o}C

Specific heat capacity of ice = 2.05 J/g^{o}C

Formula used to calculate the energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass

C = specific heat capacity

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 46 g \times 2.05 J/g^{o}C \times (100 - (-25))^{o}C\\= 11787.5 J (1 J = 0.001 kJ)\\= 11.787 kJ

Thus, we can conclude that the total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.

7 0
3 years ago
PLEASE HELPPPP! HOW DO I DO THIS???
kow [346]

Answer:

1552.83J Released

Explanation:

1. mass/m=225

Initial temp:86C, final:32.5C

Changed Temp: 32.5-86= -53.5C

s=0.129 J/gC

Formula: q= m times s times changed Temp.

q=(225)(0.129)(-53.5)

q= -1552.83 J

q=1552.83 J Released

8 0
3 years ago
Some oxygen gas takes up a volume of 2.00 liters at 0.99 atm and 273 K. Its volume doubles and its temperature decreases to 137
nataly862011 [7]

Answer:

The answer to your question is : letter B. 0.25 atm

Explanation:

To solve this problem we need to use the combined gas law:

    <u>P₁V₁</u>   =    <u>P₂V₂</u>

      T₁              T₂

Data

P1 = 0.99 atm  V1 = 2 l  T1 = 273K

P2 = ?               V2 = 4 l   T2 = 137K

Now, the clear P2 from the equation and we get

       P2 = P1V1T2 / T1V2

Substitution         P2 = (2 x 0.99 x 137)/(273 x 4)

       P2 = 271.26 / 1092

Result       P2 = 0.248 atm ≈ 0.25 atm

5 0
3 years ago
Read 2 more answers
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