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Greeley [361]
3 years ago
6

Allen is carrying out reactions in a lab. One of the products in all reactions is found to be either a precipitate, a gas, or wa

ter. What is common between all these reactions?
Chemistry
2 answers:
juin [17]3 years ago
4 0

Answer:

Decomposition reaction.

Explanation:

There is formation of a precipitate or evolution of gas or formation of water generally during decomposition reactions.

They involve breaking of a compound into two or more new compounds or one or more element.

Example:

Decomposition of calcium carbonate.

CaCO_{3}--->CaO(s)+CO_{2}(g)

H_{2}SO_{3}--->H_{2}O+SO_{2}(g)

Artist 52 [7]3 years ago
3 0
All decomposition reactions. 
Hope this helps!(: 
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What is the voltage of the voltaic cell Zn|Zn2+||Cu2+|Cu at 298 K if [Zn2+] = 0.2 M and [Cu2+] = 4.0 M? Cu2+ + 2e- → Cu Eo = +0.
OLga [1]

Answer : The voltage of the voltaic cell is 1.14 V

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Oxidation half reaction:  Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction:  Cu^{2+}+2e^-\rightarrow Cu

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu

To calculate the E^o{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=E^o_{(Cu^{2+}/Cu)}-E^o_{(Zn^{2+}/Zn)}

Putting values in above equation, we get:

E^o_{cell}=(+0.34V)-(-0.76V)

E^o_{cell}=1.1V

Now we have to calculate the emf or voltage of the cell.

Using Nernest equation at 298 K :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Cu^{2+}]}

where,

n = number of electrons in oxidation-reduction reaction = 2

E_{cell} = ?

Now put all the given values in the above equation, we get:

E_{cell}=1.1-\frac{0.0592}{2}\log \frac{0.2}{4.0}

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Therefore, the voltage of the voltaic cell is 1.14 V

5 0
3 years ago
1/2 * m * v ^ 2 = mgh
viktelen [127]

C. the square root of 2gh

Explanation:

The square root of 2gh is equivalent to Torricelli's law in the equation.

  given expression:

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 to find v, we make it the subject of the expression:

    *multiply both sides of the equation by 2:

             

                     2 x( \frac{1}{2} m v² )= 2 (mgh)

                                      mv²  = 2mgh

    *cancel the mass, m appearing on both sides:

                                    v²  = 2gh

  * find the square root of both side

                                     v = √2gh

Learn more:

Expression brainly.com/question/11207748

#learnwithBrainly

4 0
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