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IRINA_888 [86]
3 years ago
7

How does the amplitude of a wave show how much energy is in the wave?

Chemistry
2 answers:
Temka [501]3 years ago
8 0

Answer:

energy

Explanation:

The amplitude of a wave shows how much <u>energy</u> the wave possesses.

kykrilka [37]3 years ago
4 0

Answer: The amplitude of a wave is how the wave is measured from the rest position or midline to the top of a crest or bottom of a trough, measured in meters. ... It turns out that the amplitude tells you how much energy is in the wave. A high amplitude wave is a high-energy wave, and a low-amplitude wave is a low-energy wave.

Explanation:

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A 20.0 mL sample of a NaCl solution has a mass of 21.040g. After the solution is evaporated to dryness, the dry salt residue has
Vilka [71]
Mass NaCl = 4.348
Mass solution = 21.040 - 4.348 = 16.692
mass/mass % =
4.348/16.692
= 26%
mass/vol % =
21.7%
Molecular mass of NaCl = 58.5
Moles of NaCl = 0.074
Volume of solution = 0.02 L
Molarity = 3.7 mol/Liter
7 0
4 years ago
Substances have a fixed arrangement of atoms. true or false (NO LINKS PLEASE)
KATRIN_1 [288]

Answer:

True

Explanation:

5 0
3 years ago
If the temperature of 15 grams of water changes from 21C to 24C, how many joules of heat were involved? Show work
goblinko [34]

Answer:

189 Joules

Explanation:

Applying,

Q = cm(t₂-t₁)............. equation 1

Where Q = Heat, c = specific heat capacity of water, m = mass of water, t₁ = Initial Temperature, t₂ = Final temperature.

From the question,

Given: m = 15 grams = 0.015 kg, t₁ = 21 °C, t₂ = 24 °C

Constant: c = 4200J/kg.°C

Substitute these values into equation 1

Q = 0.015×4200×(24-21)

Q = 0.015×4200×3

Q = 189 Joules

6 0
3 years ago
10 ejemplos de disoluciones identificando el soluto y el solvente y el tipo de disolucion que corresponde
Keith_Richards [23]

Answer:

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4 0
3 years ago
using the soubility curve what is the solubilityof nh4cl in 10 mL of water at a temperature of 60 degrees Celsius​
lukranit [14]

Answer:

Please, see attached two figures:

  • The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.

  • The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.

  • Answer: <u>5.5g</u>

Explanation:

The red  arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the <em>solubility</em> of <em>NH₄Cl.</em>

From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.

Assuming density 1.0 g/mol for water, 10 mL of water is:

            10mL\times 1.0g/mL=10g

Thus, the solutibily is:

      10gWater\times 55gNH_4Cl/100gWater=5.5gNH_4Cl

5 0
3 years ago
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