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IRINA_888 [86]
3 years ago
7

How does the amplitude of a wave show how much energy is in the wave?

Chemistry
2 answers:
Temka [501]3 years ago
8 0

Answer:

energy

Explanation:

The amplitude of a wave shows how much <u>energy</u> the wave possesses.

kykrilka [37]3 years ago
4 0

Answer: The amplitude of a wave is how the wave is measured from the rest position or midline to the top of a crest or bottom of a trough, measured in meters. ... It turns out that the amplitude tells you how much energy is in the wave. A high amplitude wave is a high-energy wave, and a low-amplitude wave is a low-energy wave.

Explanation:

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Answer:

fusion reaction

The simple answer is that the sun, like all stars, is able to create energy because it is essentially a massive fusion reaction. Scientists believe that this began when a huge cloud of gas and particles (i.e. a nebula) collapsed under the force of its own gravity – which is known as Nebula Theory.

Explanation:

hope this helps

5 0
3 years ago
Which of the substances shown below most likely exhibit hydrogen bonding with other identical
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Is Naci a metal or none metel
Schach [20]

Answer:

Salt (NaCl) is an ionic bond that consists of Sodium (Na) which is a metal with positive charge combines with Chlorine (Cl), a nonmetal with a negative charge.

Explanation:

3 0
3 years ago
How many grams of h2o are needed to produce 45g of NO
schepotkina [342]

We need (i) the stoichiometric equation, and (ii) the equivalent mass of dihydrogen.
Explanation:
1
2
N
2
(
g
)
+
3
2
H
2
(
g
)
→
N
H
3
(
g
)
11.27

g
of ammonia represents
11.27
⋅
g
17.03
⋅
g
⋅
m
o
l
−
1

=

?
?

m
o
l
.
Whatever this molar quantity is, it is clear from the stoichiometry of the reaction that 3/2 equiv of dihydrogen gas were required. How much dinitrogen gas was required?
4 0
2 years ago
If a buffer solution is 0.220 M in a weak acid ( Ka=7.4×10−5) and 0.540 M in its conjugate base, what is the pH?
valkas [14]

Answer: the pH of the solution is 4.52

Explanation:

Consider the weak acid as Ha, it is dissociated as expressed below

HA     H⁺  +  A⁻

the Henderson -Haselbach equation can be expressed as;

pH = pKa + log( [A⁻] / [HA])

the weak acid is dissociated into H⁺ and A⁻ ions in the solution.

now the conjugate base of the weak acid HA is

HA(aq) {weak acid}     H⁺(aq)  +  A⁻(aq) {conjugate base}

so now we calculate the value of Kₐ as well as pH value by substituting the values of the concentrations into the equation;

pKₐ = -logKₐ

pKₐ = -log ( 7.4×10⁻⁵ )

pKₐ = 4.13

now thw pH is

pH = pKₐ  + log( [A⁻] / [HA])

pH = 4.13 + log( [0.540] / [0.220])

pH = 4.13 + 0.3899

pH = 4.5199 = 4.52

Therefore the pH of the solution is 4.52

6 0
3 years ago
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