The molarity of the resulting solution obtained by diluting the stock solution is 3 M
<h3>Data obtained from the question </h3>
- Molarity of stock solution (M₁) = 15 M
- Volume of stock solution (V₁) = 500 mL
- Volume of diluted solution (V₂) = 2.5 L = 2.5 × 1000 = 2500 mL
- Molarity of diluted solution (M₂) =?
<h3>How to determine the molarity of diluted solution </h3>
M₁V₁ = M₂V₂
15 × 500 = M₂ × 2500
7500 = M₂ × 2500
Divide both side by 2500
M₂ = 7500 / 2500
M₂ = 3 M
Thus, the volume of the resulting solution is 3 M
Learn more about dilution:
brainly.com/question/15022582
#SPJ1
P = nRT/V
P = 3.5 x 10^-3 x 0.082 x 298 /0.5
P = 0.171 m Hg
P = 171 mm Hg
hope this helps
Particles in a: gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.!
<span>Enthalpy
change is the total heat that is absorbed or evolved in a certain reaction that
is being carried in a constant pressure system. It can be calculated by the
product of the specific heat of the substance and the difference of the final
temperature and the initial temperature. For this case, the enthalpy of combustion is given, so we simply multiply the amount of octane present to the enthalpy given to determine the total heat that is released.
Heat = 75 g ( 1 mol / 114.23 g ) (- 5500 kJ / mol ) = - 3611.14 kJ
The negative sign in the calculated value represents that this heat is being released in the process.</span>
