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Delvig [45]
3 years ago
6

A small cylinder of helium gas used for filling balloons has a volume of 2.20 L and a pressure of 14300 kPa at 25 ∘C. Part A How

many balloons can you fill if each one has a volume of 1.20 L and a pressure of 1.22 atm at 25 ∘C?
Chemistry
1 answer:
Korvikt [17]3 years ago
7 0

Answer:

You can fill 212 balloons.

Explanation:

First we <u>calculate the helium moles in the small cylinder</u>, using <em>PV=nRT:</em>

  • P =  14300 kPa ⇒ 14300 * 0.009869 = 141.13 atm
  • V = 2.20 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 25 °C ⇒ 25 + 273.16 = 298.16 K

141.13 atm * 2.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

  • n = 12.70 mol

Then we <u>calculate the number of moles that can fit in a single balloon</u>:

  • 1.22 atm * 1.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K
  • n = 0.0599 mol

Finally we <u>divide the total number of available moles by the number of moles in a single balloon</u>:

  • 12.70 mol / 0.0599 mol = 212.09

So the answer is that you can fill 212 balloons.

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Answer:

21 KJ/mol

Explanation:

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<u>Molecule B</u>

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In this molecule, we have 1 Methyl-methyl <em>gauche </em>interaction only, so:

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In this molecule, we have 1 Methyl-methyl <em>gauche </em>interaction only, so:

3.8 KJ/mol

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In this molecule, we have a Methyl-methyl <em>eclipse </em>interaction a Methyl-H <em>eclipse </em>interaction and an H-H <em>eclipse</em> interaction, so:

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The structures with higher energies would be less stable. In this case, structures B and F with an energy value of 21 KJ/mol (see figure 2).

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