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Nikitich [7]
3 years ago
5

Which of these properties would be possessed by both acids and bases? note: we do not mean mixing both in the same solution. we

mean comparing a solution of an acid and a solution of a base. 1. they would taste bitter, if you were unwise enough to taste them. 2. they would react with metals and produce hydrogen gas. 3. they conduct electricity. 4. they turn litmus green. 5. they have a ph greater than 7. site:.com?
Chemistry
1 answer:
Firdavs [7]3 years ago
5 0
Answer is: <span>3. they conduct electricity.
1) acids taste sour, bases taste bitter.
2) acid </span><span>would react with metals and produce hydrogen gas:
Ca(s) + 2HCl(aq) </span>→ CaCl₂(aq) + H₂(g).
3) Acids and bases give ions in water solutions, so <span>they conduct electricity.
</span>

An Arrhenius base is a substance that dissociates in water to form hydroxide ions (OH⁻<span>). 
In this example lithium hydroxide is an Arrhenius base:</span>

LiOH(aq) → Li⁺(aq) + OH⁻(aq).

An Arrhenius acid is a substance that dissociates in water to form hydrogen ions or protons (H⁺<span>). 
For example hydrochloric acid: HCl(aq) → H</span>⁺(aq) + Cl⁻(aq).

4) red litmus turn blue whe base is drop on it and blue litmus turn red when acid is drop on it.

5) bases have pH greater than 7, acids have pH less than 7.

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How many grams of CuF2 are needed to make a 2.8 M solution
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Molarity is given as,

                              Molarity  =  Moles / Volume of Solution  ----- (1)

Also, Moles is given as,

                              Moles  =  Mass / M.mass

Substituting value of moles in eq. 1,

                              Molarity  =  Mass / M.mass × Volume

Solving for Mass,

                              Mass  =  Molarity × M.mass × Volume  ---- (2)

Data Given;

                  Molarity  =  2.8 mol.L⁻¹

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                  Volume  =  1 L (I have assumed it because it is not given)

Putting values in eq. 2,

                              Mass  =  2.8 mol.L⁻¹ × 101.5 g.mol⁻¹ × 1 L

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5 0
3 years ago
Suppose an ice cube weighing 36.0 g at a temperature of 10°C is placed in 360 g water at a temperature of 20°C. Calculate the te
Scilla [17]

Answer:

10.44 °C

Explanation:

When the thermal equilibrium is reached, both of the substances have the same final temperature (T). The liquid water will lose heat, and the ice cube will absorb this heat. The temperature of the ice will increase until it reaches 0°C, at this temperature, it will change of phase for liquid, absorbing heat, but without a change in the temperature. Then the temperature will increase until the equilibrium.

By the energy conservation, the total amount of heat must be equal to 0:

Qice + Qmelting + Qliquid1 + Qliquid2 = 0

Liquid 1 is the ice after melting, and liquid 2 the liquid that was already at the flask. When there's a change of temperature:

Q = n*c*ΔT, where n is the number of moles, c is the heat capacity and ΔT is the temperature change (final - initial). The temperature variation in °C is equal in K, so the temperature may be used in °C.

The melting heat is:

Q = n*Hfus, Hfus = 6007 J/mol

The molar mass of the water is 18 g/mol, so the number of moles of the water and the ice are:

nwater = nliquid1 = 360/18 = 20 moles

nice = 36/18 = 2 moles

Qice + Qmelting + Qliquid1 + Qliquid2 = 0

2*38*(0 - (-10)) + 2*6007 + 2*75*(T - 0) + 20*75*(T - 20) = 0

760 + 12014 + 150T + 1500T - 30000 = 0

1650T = 17226

T = 10.44 °C

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