<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
Molarity of acetic acid solution = 0.200 M
Volume of solution = 1 L
Putting values in above equation, we get:
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
We are given:
= negative logarithm of acid dissociation constant of acetic acid = 4.74
pH = 5.00
Putting values in above equation, we get:
To calculate the mass of sodium acetate for given number of moles, we use the equation:
Molar mass of sodium acetate = 83.06 g/mol
Moles of sodium acetate = 0.364 moles
Putting values in above equation, we get:
Hence, the mass of sodium acetate that must be added is 30.23 grams
Answer:
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Explanation:
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Answer: Fe<em>(aq)</em>+S<em>(aq)</em>=FeS<em>(s)</em>
Explanation: The Sodium and Bromine are spectator ions because they don't react with anything, you can see this by writing the ionic equation like so:
1.) Molecular formula (given): FeBr2 (aq)+Na2S (aq)= FeS(s)+2NaBr(aq)
Each dissolved FeBr2 breaks up into one Fe with a charge of 2+ and two Br with a negative charge. This gives you:
Fe(aq)+ 2Br(aq)+Na2S(aq)=FeS(s)+2NaBr
2.) Now repeat what was shown with the other compounds in the given molecular formula, and pay attention to the states that each ion is in (solid, liquid, aqueous, gas) because this will give you the ionic equation, which from there you can get rid of any ions that don't change amount or state.
3.) Ionic formula: Fe(aq)+ <u>2Br(aq)</u>+<u>2 Na(aq)</u>+S (aq)=FeS(s)+<u>2 Na(aq)+2Br(aq)</u>
4.)When you've derived a total ionic equation (above), you'll find that some ions appear on both sides of the equation in equal numbers. For example, in this case two Na cations and two Br anions appear on both sides of the total ionic equation. What does this mean? It means these ions don't participate in the chemical reaction. They're present before and after the reaction. Nothing happens to them. So those are removed and you're left with the net ionic: Fe(aq)+S(aq)=FeS(s)
Hope this helps :)
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