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maria [59]
3 years ago
13

an, 13 Students set up two environments see which one best supports growth of hibiscus flowers. One environment is created as a

desert, using The plant is exposed to high temperatures. The a tropical other environment is create exposing the forest, using soil and the plant to high temperatures. What is variable used in the investigation? 5.2(A) CA The temperature The environmen The type of flower The amount of sunlight in D

Chemistry
1 answer:
Assoli18 [71]3 years ago
8 0
B. The Enviroment. The Soil and Humidity are differant. They both have high tematures, they use the same flowers in both, Hibiscus. The tropical environent should help the Hiviscus grow better.
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What is the final volume (l) of a 10.0 l system that has the pressure quartered?
mihalych1998 [28]
According to Boyle's Law, P1V1 = P2V2

where P1 and V1 are initial pressure and volume respectively. P2 and V2 are final pressure and volume receptively.

Given: P2 = 4 P1 and V1 = 10.0l

∴ V2 = 2.5 l

Answer: Final volume of system is 2.5 l


5 0
2 years ago
Why are the fruit and vegetable sections called the produce aisle?
QveST [7]
Fruits and vegetables are in the produce aisle because they are plants, and plants are producers.
Producers are organisms that create energy on their own through various processes depending on the organism. 
6 0
3 years ago
Which layer contains almost 90% of the atmosphere's total mass?
Afina-wow [57]
The answer is the troposphere

4 0
3 years ago
Help!!! chemistry electrolysis
Tpy6a [65]
Electrolysis can be used to separate a substance into its original components/elements and it was through this process that a number of elements have been discovered and are still produced in today's industry.
5 0
3 years ago
7. Diethyl ether burns in air according to the following equation. C4H10O(l) + 6O2 (g) → 4CO2 (g) + 5H2O(l) If 7.15 L of CO2 is
iren [92.7K]

From the stoichiometry of the combustion reaction, we can see that 7.4 L of oxygen is consumed.

<h3>What is combustion?</h3>

Combustion is a reaction in which a substance is burnt in oxygen. The equation of the reaction is; C4H10O(l) + 6O2 (g) → 4CO2 (g) + 5H2O(l)

We can obtain the number of moles of CO2 from;

PV = nRT

n = 1.02 atm * 7.15 L/0.082 atm LK-1mol-1 * (125 + 273) K

n = 7.29 /32.6

n = 0.22 moles

If 6 moles of oxygen produces 4 moles of CO2

x moles of oxygen produces 0.22 moles of CO2

x = 0.33  moles

1 mole of oxygen occupies 22.4 L

0.33 moles of oxygen occupies 0.33 moles *  22.4 L/ 1 mole

= 7.4 L of oxygen

Learn more about stoichiometry: brainly.com/question/13110055

#SPJ1

6 0
2 years ago
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