The answer is; D
Solvation is the process by which the molecules of a solute interact with those of a solvent to form solvates. The interaction involves the formation of temporary bonds between the molecules of the elements. These bonds in this rection absorb energy from the atmosphere hence the reaction feels cold to the touch. This is called an endothermic reaction.
Answer:i don't rlly get the question but this is what i found on the internet :/
Explanation:
When the temperature is increased, the position of equilibrium moves in the endothermic direction to reduce the temperature. ... This means that as the temperature is increased, the position of equilibrium moves to the left, and the yield of ammonia decreases.
The number of moles of the gas sample present at the end is 0.78 moles.
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Number of moles of the gas</h3>
PV = nRT
V = nRT/P
At a constant volume, V;
n₁RT₁/P₁ = n₂RT₂/P₂
n₁T₁/P₁ = n₂T₂/P₂
n₂ = (n₁T₁P₂)/(P₁T₂)
where;
- T₁ is initial temperature = 21.7⁰C = 294.7 K
- T₂ is final temperature = 28.1⁰C = 301.1 K
n₂ = (3 x 294.7 x 0.998)/(3.75 x 301.1)
n₂ = 0.78 moles
Thus, the number of moles of the gas sample present at the end is 0.78 moles.
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Answer: The correct answer is D.
Explanation:
As you can see in every step of the pathway, ATP is not generated directly. Although, in the oxidative phase, molecules of NADPH are produced and these can be used for synthesize ATP indirectly; the NADPH molecules are hihgly demanded in tissues that carry out constantly synthesis of fatty acids, such as liver.
Therefore the correct answer is D.
The Balanced chemical equation of reaction of Borane with oxygen is as follow,
B₂H₆ + 3O₂ -----> 2HBO₂ + 2H₂O
According to this equation 27.66 g (1 mole) of B₂H₆ reacts with oxygen to produce 36 g (2 moles) of water.
The amount of water produced when 19.2 g of B₂H₆ reacted is calculated as follow,

=

Solving for x,
x = (36 g of H₂O ₓ 19.2 g of H₂B₆) / 27.66 g of B₂H₆
x =
24.98 g of H₂O
Result:
24.98 g of water is produced when 19.2 g of B₂H₆ is reacted with excess of oxygen.