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liq [111]
3 years ago
13

A mixture of MgCl2 and NaCl has an initial mass of 0.4015 g. Excess AgNO3(aq) was added and 1.032 g of precipitate, AgCl(s), was

recovered. How many moles of MgCl2 were in the original mixture?
Chemistry
1 answer:
zlopas [31]3 years ago
4 0

Answer:

8.909*10^-4 moles

Explanation:

The mixture contains MgCl_{2} and NaCl with a total mass of 0.4015 g. The mass of precipitate AgCl(aq) is 1.032 g and it has a molar mass of 143.32 g/mol. Therefore, the moles of the precipitate is:

n = 1.032/143.32 = 7.2007*10^-3 moles

Molar mass of NaCl = 58.44 g/mol and the molar mass of MgCl_{2} is 95.21 g/mol. Let the mass (g) of MgCl_{2}  in the original mixture be 'x'. Thus:

7.2007*10^-3 = (0.4015-x)/58.44 + 2x/95.21

(7.2007*10^-3)*58.44*95.21 = 95.21(0.4015-x) + 2x(58.44)

40.06505 = 38.227 -95.21x + 116.88x

40.06505 - 38.227 = -95.21x + 116.88x

1.83805 = 21.67x

x = 1.83805/21.67 = 0.0848 g

moles of MgCl_{2} = 0.0848g/95.21 g/mol = 8.909*10^-4 moles

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Calcule la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) que se preparó al mezclar, en un recipiente aforado, 4 mo
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Considerando la definición de molaridad, la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) es 0.5 \frac{moles}{litro}.

La molaridad es una medida de la concentración de un soluto en una disolución que se define como el número de moles de soluto que están disueltos en un determinado volumen.

La molaridad de una solución se calcula dividiendo los moles del soluto por el volumen de la solución:

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La Molaridad se expresa en las unidades \frac{moles}{litro}.

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Reemplazando en la definición de molaridad:

Molaridad=\frac{4 moles}{8 litros}

Resolviendo:

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Finalmente, la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) es 0.5 \frac{moles}{litro}.

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