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2 years ago

Can someone please help me !

Mathematics

1 answer:

Schach [20]2 years ago

8 0

$2)~3x\to\text{Linear Monomial, because it's of 1st degree.}\to B\\\\
3)~2x^4-x+5\to\text{Quartic Trinomial, because it's of 4th degree.}\to C\\\\
4)~(2x^2-5x+6)+(5x^2-3x+4)=(2x^2+5x^2)-(5x+3x)+(6+4)\\\\
=7x^2-8x+10\to A$

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An electronics company wants to compare the quality of their cell phones to the cell phones from three of their competitors. The

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Answer:

The treatment should be stated by the four companies,since it more interested in the quality among each of the companies to be compared.

Step-by-step explanation:

From the example given, Since an electronic company wants to differentiate their cell phones quality to the cell phones from their three main competitors.

If ANOVA is used to determine the average number of defects, then the treatment should be defined for the four companies because it is more interested in comparing the quality among the different companies.

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3 years ago

Please help. I’ll mark you as brainliest if correct!!!!! ON B!

Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

Because if 1,3 times 130

than 1.25 equals 125 so she would only earn 5 dollars less money

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3 years ago

2. In the diagram below, secants PT and PU have been drawn from exterior point P such that the four arcs

scoundrel [369]

Answer:

(a) x = 30°

(b) mRS = 30°

mST = 120°

mTU = 120°

mUR = 90°

Step-by-step explanation:

(a) In the picture attached, the diagram is shown.

Given that m arc RS = x, from the ratios:

m arc ST = 4x

m arc TU = 4x

m arc UR = 3x

The addition of the four arcs must be equal to 360°, then:

x + 4x + 4x + 3x = 360°

12x = 360°

x = 360°/12 = 30°

(b) m arc RS = x = 30°

m arc ST = 4x = 4*30° = 120°

m arc TU = 4x = 4*30° = 120°

m arc UR = 3x = 3*30° = 90°

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3 years ago

Which equation does NOT graph a line? A) y = 5 B) y = -3x3 C) y = 2 3 x D) y = −8x

kotykmax [81]

B) y = -3x3

-----------------------------------

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2 years ago

Read 2 more answers

Which answer best describes the complex zeros of the polynomial function?

marysya [2.9K]

Answer-

D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.

Solution-

The given polynomial is,

$f(x)=x^3-x^2+6x-6$

The zeros of the polynomials are,

$\Rightarrow f(x)=0$

$\Rightarrow x^3-x^2+6x-6=0$

$\Rightarrow x^2(x-1)+6(x-1)=0$

$\Rightarrow (x^2+6)(x-1)=0$

$\Rightarrow (x^2+6)=0,(x-1)=0$

$\Rightarrow x=\sqrt{-6},\ x=1$

$\Rightarrow x=1,\ \pm \sqrt6i$

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1

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3 years ago