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3 years ago

1. Looking at the planet vs. eccentricity table, which two planets have the greatest eccentricity?

Physics

1 answer:

AVprozaik [17]3 years ago

6 0

Answer:

Pluto & Mercury

Explanation:

Pluto's eccentricity is 0.248

Mercury's eccentricity is 0.206

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5. How far can a car travel in 14 hours while going at a speed of 75 miles per hour?

Gemiola [76]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Here we go ~

Speed of the car is 75 miles per hour and it travels for 14 hours. so the distance travelled by it in the given period of time can be calculated using this formula ~

$\qquad \sf \dashrightarrow \: d = v \sdot t$

$\qquad \sf \dashrightarrow \: d = 75 \times 14$

$\qquad \sf \dashrightarrow \: d = 1050 \: \: miles$

so, it can travel 1050 miles in 14 hours

5 0

2 years ago

Read 2 more answers

What is the mass of a car that weighs 19,000 N on earth?

Anna71 [15]

Divide by 9.8 I think
so <span>1938.77551</span>

8 0

3 years ago

If atmospheric pressure on a certain day is 749 mmhg, what is the partial pressure of nitrogen, given that nitrogen is about 78%

VARVARA [1.3K]

The partial pressure of nitrogen is about 584 mmHg.

7 0

3 years ago

3 A rocket of mass 1200 kg is travelling at 2000 m/s. It fires its engine for 1 minute. The forward thrust provided by the rocke

natita [175]

The impulse shared by the object equals the difference in momentum of the object. In equation form,

F • t = m • Δ v. In a collision, objects experience an impulse; the impulse causes and is equal to the difference in momentum.

<h3>How to calculate thrust provided by the rocket engines is 10 kN (10 000 N).?</h3>

a)There is this impulse-momentum change equation.

$where m$ is the mass of a body, $F$ is a force acting to the body, $t$ is time and $D E L A T A N\}=V_{2}-V_{1}$ is the change of velocity.We consider everything is happen along a straight line, and gravitation does not participate.So, the increase of momentum is $\mathrm{F}^{*} \mathrm{t}=10000 \mathrm{~N} * 60$ seconds $=600000 \mathrm{~N}^{*} \mathrm{~s}=600000\left(\mathrm{~kg}^{*} \mathrm{~m}\right)^{*} \mathrm{~s} / \mathrm{s}^{\wedge} 2=600000 \mathrm{~kg}{ }^{*} \mathrm{~m} / \mathrm{s}$.$

We consider everything exits happen along a straight line, and gravitation does not participate.

So, the increase of momentum is F×t = 10000 N × 60 seconds = 600000 N*s = 600000 (kg*m)*s/s^2 = 600000 kg*m/s.

$\Delta(\mathrm{V})=\frac{\mathrm{F.t}}{\mathrm{m}}=\frac{600000}{1200}=500 \mathrm{~m} / \mathrm{s} .$

New velocity after engine was firing during 60 seconds is 2000 + 500 = 2500 m/s.

To learn more about Impulse-momentum, refer

brainly.com/question/20586658

#SPJ9

5 0

1 year ago

Explain each stage of communication process

zaharov [31]

Explanation:

hope this would be the right answer ..

3 0

3 years ago