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Kitty [74]
3 years ago
12

A rope vibrates every 0.5 s. What is the frequency of the waves? 5 Hz 2 Hz 0.5 Hz 1 Hz

Physics
1 answer:
yulyashka [42]3 years ago
4 0
The answer is 2Hz

Using the formula f= 1/T we can plug in .5 for T and solve for frequency.
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A manometer that is filled with water (rho=1000 kg/m3) is connected to a wind tunnel to measure the pressure inside the test sec
Anna [14]

To develop this problem it is necessary to apply the concepts performed to the absolute pressure based on the reference pressure (atmospheric) and the pressure that is generated due to the height of the column of the measured liquid.

In mathematical terms the previous concept can be expressed as

P_{abs} = P_{atm} -\rho gh

Where

P_{atm}=Atmospheric Pressure

\rho =Density

g = Gravitational acceleration

h = Height

Our values are given as

h = 10*10^{-3}m

g = 9.8m/s

\rho_{water} = 1000kg/m^3

P_{atm} = 100kPa

Replacing we have then that

P_{abs} = P_{atm} -\rho gh

P_{abs} = 100 -(1000)(9.8)(10*10^{-3})

P_{abs} = 99.9019kPa

Therefore the absolute pressure in the test section is 99.9019kPa

6 0
3 years ago
Four forces of magnitude 10N,15N, 4N, 6N act on on object in the direction North West, East and South respectively, find their m
maria [59]

Magnitude 17 root

Hope it Helps! Please mark as Brainliest!

7 0
3 years ago
What force is required to accelerate a 385 kg couch at 0.2 m/s^2 ?
Juliette [100K]

Answer:

It takes 77 N

Explanation:

Using Newton's second law of motion, F=ma (Force equals mass times acceleration. Since the mass of the couch is 385 kg and the target acceleration is 0.2 m/s, you simply multiply mass times acceleration (ma) to get the total force, or 77 N.

6 0
3 years ago
A 15-kg bicycle carrying a 50-kg boy is traveling at a speed of 5 m/s. What is the KE of the bicycle and the boy?
vovangra [49]
Together as one moving package, their mass is (15 + 50) = 65 kg.

       Kinetic energy = (1/2) (mass) (speed)²

                               = (1/2) (65 kg) (5 m/s)²

                               =  (32.5 kg) (25 m²/s²)

                               =     812.5  kg-m²/s²  =  812.5 joules .
4 0
4 years ago
The coefficient of static friction between a book and the level surface it slides on is 0.65. If the mass of the book is 0.2 kg,
just olya [345]

Answer: 1.274 N minimum force required to slide the book across the surface

Explanation:

Mass of the book = m = 0.2 kg

Normal force acting on the book,N = mg

Coefficient of friction =mu_s = 0.65

Minimum force required to slide the book across the surface= F

F=\mu_s\times N

F=0.65\times 0.2 kg\times 9.8 m/s^2=1.274 N

1.274 N minimum force required to slide the book across the surface

7 0
3 years ago
Read 2 more answers
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