A rope vibrates every 0.5 s. What is the frequency of the waves? 5 Hz 2 Hz 0.5 Hz 1 Hz

A group of workers applied 10.0 networks of force to move a crate 20.0 meter. Calculate the work

olga2289 [7]

The work done is 200 J

Explanation:

The work done by a force applied to move an object is given by:

$W= F d cos \theta$

where

F is the magnitude of the force

d is the displacement of the object

$\theta$ is the angle between the direction of the force and of the displacement

In this problem, assuming that the force applied by the workers is parallel to the direction of motion of the crate, we have:

F = 10.0 N

d = 20.0 m

$\theta=0^{\circ}$

Therefore, the work done is:

$W=(10.0)(20.0)(cos 0)=200 J$

Learn more about work here:

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4 0

4 years ago

3) Using the rating of perceived exertion scale that we

Schach [20]

Answer:

What do you mean

Explanation:

7 0

3 years ago

How do solar panels create electricity

xenn [34]

Answer:

They create electricity from the sun's rays

Explanation:

By the use of "solar cells" or "solar panel", you can trap solar energy in silicon/germanium rods, then you can convert in into electricity too. Solar powered panels convert the sun's rays into electricity by exciting electrons in silicon cells using the photons of light from the sun. This electricity can then be used to supply renewable energy to your home or business.

5 0

3 years ago

Un ladrón viaja en un auto a una velocidad excesiva de 30m/s, en dicho momento un policía de tránsito, lo observa y monta en su

tester [92]

Answer:

t = 12 s

Explanation:

To find the time in which the police reaches the thief you write the equation of motion of both thief and police:

The thief has a constant velocity, the position is then given by:

$x=vt$ (1)

The police has an acceleration, then the position is:

$x=v_ot+\frac{1}{2}at^2$ (2)

the time in which the police reaches the thief is when their positions are equal, that is, when expression (1) equals expression (2). But before you calculate the acceleration of the police:

$a=\frac{v-v_o}{t}\\\\v_o=0m/s\\\\a=\frac{50m/s}{10s}=5\frac{m}{s^2}$

you replace this values in (2) and you equal the expression (1) and (2) (with vo = 0):

$vt=\frac{1}{2}at^2\\\\\frac{1}{2}at^2-vt=0\\\\(\frac{1}{2}at-v)t=0$

one root is t = 0s, but it is omitted because is the momment in which the thief pass in front of the police. The other root is:

$\frac{1}{2}at-v=0\\\\t=\frac{2v}{a}=\frac{(2)(30m/s)}{5m/s^2}=12s$

hence, the time is 12 s

8 0

4 years ago

Given that y is the vertical displacement of a wave at anytime and A is the amplitude of the wave, w is the angular speed of the

denis-greek [22]

Explanation:

The general equation describing a wave is:

y(x,t) = A sin(kx - wt)

Let's say that for a particular wave on a string the equation is:

y(x,t) = (0.9 cm) sin[(1.2 m-1)x - (5.0 s-1)t]

(a) Determine the wave's amplitude, wavelength, and frequency.

(b) Determine the speed of the wave.

(c) If the string has a mass/unit length of m = 0.012 kg/m, determine the tension in the string.

(d) Determine the direction of propagation of the wave.

(e) Determine the maximum transverse speed of the string.

Solutions

Part (a): The wave's amplitude, wavelength, and frequency can be determined from the equation of the wave:

y(x,t) = (0.9 cm) sin[(1.2 m-1)x - (5.0 s-1)t]

The amplitude is whatever is multiplying the sine.

A = 0.9 cm

The wavenumber k is whatever is multiplying the x:

k = 1.2 m-1The wavelength isl=2pk= 5.2 m

The angular frequency w is whatever is multiplying the t.

w = 5.0 rad/sf=w2p= 0.80 Hz

Part (b): The wave speed can be found from the frequency and wavelength:

v = f l = 0.80 * 5.2 = 4.17 m/s

Part (c): With m = 0.012 kg/m and the wave speed given by:v=(Tm)½

This gives a tension of T = m v2 = 0.012 (4.17)2 = 0.21 N.

Part (d): To find the direction of propogation of the wave, just look at the sign between the x and t terms in the equation. In our case we have a minus sign:

y(x,t) = (0.9 cm) sin[(1.2 m-1)x - (5.0 s-1)t]

A negative sign means the wave is traveling in the +x direction.

A positive sign means the wave is traveling in the -x direction.

Part (e): To determine the maximum transverse speed of the string, remember that all parts of the string are experiencing simple harmonic motion. We showed that in SHM the maximum speed is:

vmax = Aw

In this case we have A = 0.9 cm and w = 5.0 rad/s, so:

vmax = 0.9 * 5.0 = 4.5 cm/s

maybe this should help

6 0

3 years ago