Question

Write a balanced equation for the reaction of NaCH3COO (also written as NaC2H3O2) and HCl

Answer 1

The chemical reaction of the reactants, NaCH3COO and HCl, is written as follows:

NaCh3COO + HCl = NaCl + CH3COOH

To balance it, the number of atoms of an element in one side should be equal to the other side. By looking at the reaction, I believe it is already balanced. They have 1 is to 1 ratios.

Answer 2

Answer:

$CH_3COONa~+~HCl~->~CH_3COOH~+~NaCl$

Explanation:

This is an acid-base reaction in which the HCl is the acid and the $CH_3COONa$ is the base.

In the balanced reaction, we will have a double replacement reaction. In which the cation of  $CH_3COONa$ (in this case $Na^+$) will be exchanged by the hydronium ion $H^+$ from the $HCl$. Similarly the anion of $HCl$ ($Cl^-$ ) would bond with the cation $Na^+$ to form $NaCl$.