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solong [7]
2 years ago
14

a solid substance a is soluble in water to the extent of 10 mg/ml of water at 25oc and 100 mg/ml of water at 100oc. you have a s

ample that contains 100 mg of a and 25 mg of an impurity b. a and b have the same solubility behavior. if one 10ml portion of water was used for the recrystallization, what was the % recovery of a
Chemistry
1 answer:
DiKsa [7]2 years ago
3 0

Answer:

join the provisonal IRA and help free and unite ireland

Explanation:

fight aganst the english oppressors and free ireland

erinn go braugh

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When does the object change direction?
Tatiana [17]

Answer:

50distance and 10minutes time

Explanation:

because it's the best object

4 0
3 years ago
What volume (mL) of the sweetened tea described in Example 1 contains the same amount of sugar (mol) as 10 mL of the soft drink
S_A_V [24]

The question is incomplete, the complete question is:

What volume (mL) of the sweetened tea described in Example 3.14 contains the same amount of sugar (mol) as 10 mL of the soft drink in this example. The example is attached below.

<u>Answer:</u> 75 mL of sweetened tea will contain the same amount of sugar as in 10 mL of soft drink

<u>Explanation:</u>

We first calculate the number of moles of soft drink in a volume of 10 mL

The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}} .....(1)

Taking the concentration of soft drink from the example be = 0.375 M

Volume of solution = 10 mL

Putting values in equation 1, we get:

0.375=\frac{\text{Moles of sugar in soft drink}\times 1000}{10}\\\\\text{Moles of sugar in soft drink}=\frac{0.375\times 10}{1000}=0.00375mol

<u>Calculating volume of sweetened tea:</u>

Moles of sugar = 0.00375 mol

Molarity of sweetened tea = 0.05 M

Putting values in equation 1, we get:

0.05=\frac{0.00375\times 1000}{\text{Volume of sweetened tea}}\\\\\text{Volume of sweetened tea}=\frac{0.00375\times 1000}{0.05}=75mL

Hence, 75 mL of sweetened tea will contain the same amount of sugar as in 10 mL of soft drink

5 0
3 years ago
What is it called when particles travel from an area of high consentration to an area of low consentration?
Umnica [9.8K]
If it isn't using energy, it's called diffusion
8 0
3 years ago
2. Which of the following expressions is generally used for solubility? (1 point)
miskamm [114]

<u>Answer:</u>

For 2: The correct answer is grams of solute per 100 grams of solvent.

For 3: The correct answer is supersaturated.

For 4: the correct answer is the solubility decreases.

<u>Explanation:</u>

  • <u>For 2:</u>

Solubility is defined as the property which refers to the ability of the solute that can be dissolved in a solvent. It is defined as the number of grams of  solute per 100 grams of solvent.

  • <u>For 3:</u>

Unsaturated solution is defined as the solution in which amount of solute that is dissolved in the solvent is less.

Saturated solution is defined as the solution in which no more solute can be dissolved in the given amount of solvent.

Emulsion is defined as the dispersion of one liquid in another liquid in which it is not soluble.

Supersaturated solution is defined as the solution in which solvent contains more amount of solute than the required amount. These solutions help in the process of crystallization.

When a crystal is added to a <u>supersaturated solution</u>, more and more particles come out of the solution and this process is known as crystallization.

  • <u>For 4:</u>

According to the Henry's Law

The solubility of the gas in a liquid is directly proportional to the partial pressure of the gas.

\text{Solubility of a gas in a liquid}\propto \text{Partial pressure of the gas}

With increase in the partial pressure, the solubility of the gas in liquid also increases and vice-versa.

Hence, the correct answer is the solubility decreases.

7 0
3 years ago
Read 2 more answers
PLEASE HELP CHEMITRY!
Delicious77 [7]

Answer:

.

Explanation:

5 0
2 years ago
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