A small metal ball is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizontal
circle so that the thread describes a cone. The acceleration of gravity is 9.8 m/s2, 2.7 m, 6 kg, 31C. What is the speed of the ball when it is in circular motion? Answer in units of m/s.
1 answer:
Answer:
a) -2.1731 m⁻s
Explanation:
L= length of thread, H= height of ball from ceiling,
N/B h= l cosФ, Ф=31°, l=2.7m, g=9.8m⁻s, m= 6kg
Required to find speed v, of the ball in m⁻s
ω=√g/h, =√g/lcosФ
⇒ ω=√9.8/2.7×cos31°
= 1.992rad⁻s
Now, speed in m/s, v= r.ω
where tanФ= r/h ⇒
r= h×cos 31°
r= 2.7 × cos(31) × tan(31) =-1.0909m
v= 1.992× -1.0909 = -2.1731 m/s
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