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Stolb23 [73]
3 years ago
7

A person walks into a room that has, on opposite walls, two plane mirrors producing multiple images. Find the distances from the

person to the first three images seen in the left-hand mirror, when the person is 5.80 ft from the mirror on the left wall and 13.7 ft from the mirror on the right wall.
Physics
1 answer:
worty [1.4K]3 years ago
5 0

Answer:

Explanation:

When the person stands 5.80 ft from the mirror of the wall.

a) The first image is found by multiplying the distance of the left mirror to the person.

i.e.

2 × 5.80 = 11.6 ft

b) The second image is deduced by the addition of the distance of the first image with the distance created by the right mirror.

i.e.

(2 × 13.7 ) + 11.6

= 39 ft

c) The third image is acquired by the addition of the image presented by the left mirror and the image presented by the right mirror.

(2 × 5.80) + 39

= 50.6 ft

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C1=4F, C2=4F, C3=2F, C4=4F, C5= 9.2 F. Calculate the equivalent capacitance
grin007 [14]

The equivalent capacitance between A and B points is 2.5F.

<h3>What is parallel plate capacitor?</h3>

The two parallel plates placed at a distance apart used to store charge when electric supply is on.

The capacitance of a capacitor is given by

C = ε₀ A/d

From the given circuit C1, C2 and C3, C4 are in parallel  C1=4F, C2=4F, C3=2F, C4=4F, C5= 9.2 F

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Now , all capacitors are in series.

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Read 2 more answers
A plane wall of thickness 0.1 mm and thermal conductivity 25 W/m K having uniform volumetric heat generation of 0.3 MW/m3 is ins
juin [17]

Answer:

The maximum temperature is 90.06° C

Explanation:

Given that

t= 0.1 mm

Heat generation

q_g=0.3\ MW/m^3

Heat transfer coefficient

h=500\ W/m^2K

Here one side(left side) of the wall is insulated so the all heat will goes in to right side .

The maximum temperature will at the left side.

Lets take maximum temperature is T

Total heat flux ,q

q=q_g\times t

q=0.3\times 1000000\times 0.1 \times 10^{-3}\ W/m^2

q=30\ W/m^2

So the total thermal resistance per unit area

R=\dfrac{t}{K}+\dfrac{1}{h}

R=\dfrac{0.1\times 10^{-3}}{25}+\dfrac{1}{500}

R=0.002 K/W

We know that

q=ΔT/R

30=(T-90)/0.002

T=90.06° C

The maximum temperature is 90.06° C

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3 years ago
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