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ludmilkaskok [199]
3 years ago
6

Light illuminates two closely spaced thin slits and produces an interference pattern on a screen behind. How will the distance b

etween the fringes of the pattern differ for red light and blue light? 1. The same spacing for both 2. Closer for red light 3. Farther apart for red light
Physics
1 answer:
umka21 [38]3 years ago
3 0

Answer:

3. Farther apart for red light

Explanation:

The distance y between fringes is

y = \dfrac{\lambda L }{d},

where \lambda is the wavelength of light, L is the distance to the screen, and d is the slit separation.

Now, the wavelength \lambda_r of the red light is greater than for the wavelength \lambda_b for blue light:

\lambda_r> \lambda_b,

which means

\dfrac{\lambda_r L }{d}>\dfrac{\lambda_b L }{d},

In other words, the distance between the fringes is greater for red light, which from the options is choice 3.

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A long wire carrying a 5.0 A current perpendicular to the (xy)-plane intersects the x-axis at x = -2.00 cm. A second parallel wi
zimovet [89]

Answer:

a. 05cm from x axis

b. 8cm from x axis

Explanation:

If the net magnetic field is zero and the currents are in the same direction then the thanks point is between the currents i1 and i2 as show in the attachment below

a. Given that i1= 5A and i2=3A

Let assume the null point is xcm from current i1, then the null point will be (4-x)cm from current i2 since the total length is 4cm.

Now the magnetic field of the current i1 from the null point= to magnetic field of current i2 from the null point

B1=B2

μi1/2πx=μi2/2π(4-x)

i1/x=i2/(4-x)

5/x=3/(4-x)

20-5x=3x

8x=20

8x=2.5cm

since from the left of x axis is 2cm, then the null point is 2.5-2 which 0.5cm from the origin x axis.

The null point is 0.5cm from the origin x axis

b. If both current are flowing in opposite direction, the null point lies outside of the current.

Then with same analysis let assume the first current i1 is xcm from the null point and since the total length is 4cm the second current i2 will be (x-4)cm from the null point.

Also the magnetic field of the current i1 from the null point = to magnetic field of current i2 from the null point

B1=B2

μi1/2πx=μi2/2π(x-4)

i1/x=i2/(x-4)

5/x=3/(x-4)

5x-20=3x

2x=20

x=10cm.

This shows that the distance of the null point from current i1 is 10cm and the current i1 is 2cm from the x axis, then the null point is 10-2=8cm from the origin x axis.

The null point is 8cm from the x axis.

Check the attachment to see the diagram of the current and the null points

6 0
4 years ago
Two astronauts, each having a mass of 74 kg, are connected by a 8.53 m rope of negligible mass. They are isolated in space, orbi
AveGali [126]

Answer:

a) 2575 kgm²/s

b) 1.23 kJ

c) 0.478 rad/s

Explanation:

Given

Mass of astronauts, m = 74 kg

Length of rope, l = 8.53 m

Speed of orbit, v = 4.08 m/s

L = m1v1.x1(i) + m2v2.x2(i) = 2mv(d/2)

Thus, L = 2.m.v.(d/2)

L = 2 * 74 * 4.08 * (8.53/2)

L = 2 * 74 * 4.08 * 4.265

L = 2575.38 kgm²/s

Rotational Energy of the system

K(i) = 1/2m1v1(i)² + 1/2m2v2(i)²

K(i) = 2(1/2) * 74 * 4.08²

K(i) = 74 * 16.6464

K(i) = 1231.83 J = 1.23 kJ

Angular momentum is conserved, thus, angular velocity, w = v/r

w = 4.08 / 8.53

w = 0.478 rad/s

7 0
3 years ago
Why do materials absorb some frequencies of electromagnetic radiation and not others?
AlekseyPX
Well energy absorption by a material depends upon their atomic properties. Energy is absorbed in discrete quanta of energy as predicted by quantum mechanics only if the corresponding energy state is available either it is absorbed by electrons or nucleus depends whether it can go to permissible energy state, if not system can't absorb energy at all. 
8 0
3 years ago
In a real system of levers, wheels, or pulleys, the AMA is less than the IMA because _____.
grandymaker [24]
In a real system of levers, wheel or pulleys, the AMA (actual mechanical advantage) is less than the IMA (ideal mechanical advantage) because of the presence of friction.

In fact, the IMA and the AMA of a machine are defined as the ratio between the output force (the load) and the input force (the effort):
IMA= \frac{F_{out}}{F_{in}}
however, the difference is that the IMA does not take into account the presence of frictions, while the AMA does. As a result, the output force in the AMA is less than the output force in the IMA (because some energy is dissipated due to friction), and the AMA is less than the IMA.
5 0
3 years ago
Read 2 more answers
Skater 1 has a mass of 105.0 kg and a velocity of 2.0 m/s to the left. He
mart [117]

The final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

<h3>What is velocity?</h3>

Velocity can be defined as the ratio of the displacement and time of a body.

To calculate the final velocity of Skater 1 we use the formula below.

Formula:

  • mu+MU = mv+MV............ Equation 1

Where:

  • m = mass of the first skater
  • M = mass of the second skater
  • u = initial velocity of the first skater
  • U = initial velocity of the second skater
  • v = final velocity of the first skater
  • V = final velocity of the second skater.

make v the subject of the equation.

  • v = (mu+MU-MV)/m................ Equation 2

Note: Let left direction represent negative and right direction represent positive.

From the question,

Given:

  • m = 105 kg
  • u = -2 m/s
  • M = 71 kg
  • U = 5 m/s
  • V = -3.4 m/s.

Substitute these values into equation 2

  • v = [(105×(-2))+(71×5)-(71×(-3.4))]/105
  • v = (-210+355+241.4)/105
  • v = 386.4/105
  • v = 3.68 m/s
  • v ≈ 3.7 m/s

Hence, the final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

Learn more about velocity here: brainly.com/question/25749514

7 0
2 years ago
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