Hey there!
<span>In this case, the equation of Clapeyron is used :
R = 0.082
Volume in liters :
100.0 mL / 1000 => 0.1 L
</span>
P * V = n * R * T
15.0 * 0.1 = 0.500 * 0.082 * T
1.5 = 0.041 * T
T = 1.5 / 0.041
T = 36.5 K
Answer C
I believe your answer is 23.
Credit: answers.yahoo.com
Hope this helps!
The molarity of the acid given the data from the question is 0.30 M
<h3>Balanced equation </h3>
2HNO₃ + Ba(OH)₂ —> Ba(NO₃)₂ + 2H₂O
From the balanced equation above,
- The mole ratio of the acid, HNO₃ (nA) = 2
- The mole ratio of the base, Ba(NO₃)₂ (nB) = 1
<h3>How to determine the molarity of the acid</h3>
From the question given above, the following data were obtained:
- Volume of acid, HNO₃ (Va) = 39.7 mL
- Volume of base, Ba(NO₃)₂ (Vb) = 24 mL
- Molarity of base, Ba(NO₃)₂ (Cb) = 0.250 M
- Molarity of acid, HNO₃ (Ma) =?
MaVa / MbVb = nA / nB
(Ma × 39.7) / (0.25 × 24) = 2
(Ma × 39.7) / 6 = 2
Cross multiply
Ma × 39.7 = 6 × 2
Ma × 39.7 = 12
Divide both side by 39.7
Ma = 12 / 39.7
Ma = 0.30 M
Learn more about titration:
brainly.com/question/14356286
#SPJ1
B. I’m sorry if I’m wrong ! Wasn’t sure about this question .
