Answer: Option (b) is the correct answer.
Explanation:
According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will tend to shift the equilibrium in a direction away from the disturbance.
For example, 
Hence, expression for equilibrium constant will be as follows.
![K_{eq} = \frac{[Ca^{2+}][HCO^{-}_{3}]^{2}}{[CO_{2}][H_{2}O]}](https://tex.z-dn.net/?f=K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BCa%5E%7B2%2B%7D%5D%5BHCO%5E%7B-%7D_%7B3%7D%5D%5E%7B2%7D%7D%7B%5BCO_%7B2%7D%5D%5BH_%7B2%7DO%5D%7D)
Since, the concentration for a solid substance is considered as 1 or unity. Therefore, adding or removing a solid will not affect the equilibrium.
Thus, we can conclude that according to Le Châtelier’s Principle, the amount of solid reactant or product present does not have an impact on the equilibrium because the solid does not appear in the equilibrium constant, so adding or removing solid has no effect.
Answer:
pH = 2.56
Explanation:
The Henderson-Hasselbalch equation relates the pH to the Ka and ratio of the conjugate acid-base pair as follows:
pH = pKa + log([A⁻]/[HA]) = -log(Ka) + log([A⁻]/[HA])
Substituting in the value gives:
pH = -log(1.77 x 10⁻⁴) + log((0.0065M) / (0.10M))
pH = 2.56
Answer:
36 years
Explanation:
2 = 16 * (1/2)^n where n is the number of half lives
2/16 = (1/2)^n
1/8 = (1/2)^n
log (1/8) = log (1/2^n)
log(1/8) = n log (1/2)
log ( 1/8 ) / log(1/2) = n = 3 half lives
each half life is 12 years so 3 * 12 = 36 years
Answer: The solution to the problem expressed to he correct number of significant figures is 1.69
Explanation:
Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.
The rule applied for multiplication and division is :
The least precise number determines the number of significant figures in the answer.
As 12.0 has 3 significant digits and 7.11 also has 3 significant digits, the answer would also contain 3 significant digits.
For 
Thus the solution to the problem expressed to he correct number of significant figures is 1.69
Hello!
The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.
We have the following data:
mo (initial mass) = 20 g
m (final mass after time T) = 5 g
x (number of periods elapsed) = ?
P (Half-life) = ? (in minutes)
T (Elapsed time for sample reduction) = 8 minutes
Let's find the number of periods elapsed (x), let us see:
Now, let's find the half-life (P) of the radioactive sample, let's see:
I Hope this helps, greetings ... DexteR! =)
