Answer:
The resistance is found to be 6Ω
The current is found to be 0.66 A
Explanation:
The resistance of a conductor in terms of its dimensions is given as:
R = ρL/A
where,
R = resistance = ?
ρ = resistivity = 3 x 10⁴ Ω.m
L = Length = 4 mm = 0.004 m
A = Cross-sectional area = 0.2 mm² = 0.2 x 10⁻⁶ m²
Therefore,
R = (3 x 10⁴ Ω.m)(0.004 m)/(0.2 x 10⁻⁶ m²)
<u>R = 6 Ω</u>
Now, the potential difference between both ends of the resistor is:
ΔV = 16 V - 12 V = 4 V
Now, from Ohm's Law:
V = IR
I = V/R
I = 4 V/ 6 Ω
<u>I = 0.66 A</u>
Answer:
Series circuit
Explanation:
Because the electrical components are connected one after each other in a single loop, rather than alongside each other, forming extra loops.
The trick here is that there are two variables, Diameter of the coil and number of turns in it. So, in order to solve it, we will need two equations in D and N
Since we are making coil, formula for magnetic field will be B = μₒni/D
D = μₒni/B = 4π x 10^(-7) x (N) x (2.2) / (1.6)x10^(-3) = 1.7 x 10^(-3) x N = D
Another equation will be from the wire's length.
Total length = Circumference of one loop x No. of turns = πD x N = 2.2
We will eliminate N because we need D.
N = 2.2 / πD
Substitute in 1st equation.
1.7 x 10^(-3) x 2.2 / π = D^2
<span>
D = 0.034 m = 3.4 cm </span>
