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navik [9.2K]
4 years ago
11

The gravitational acceleration on the moon is about one-sixth the size of the gravitational acceleration on Earth. According to

Newton’s second law of motion, what happens to an astronaut who goes to the moon? The astronaut’s weight decreases because the moon’s gravitational acceleration is greater than Earth’s. The astronaut’s weight increases because the moon’s gravitational acceleration is greater than Earth’s. The astronaut’s weight decreases because the moon’s gravitational acceleration is less than Earth’s. The astronaut’s weight increases because the moon’s gravitational acceleration is less than Earth’s.
Physics
1 answer:
photoshop1234 [79]4 years ago
5 0

Answer: If the gravitacional acceleration is 1/6 of Earth's gravitational acceleration, it means that moon's gravitational acceleration is less than Earth's. Also, if the gravitational acceleration is less than Earth's, the astronaut's weight decreases since we calculate it multiplying his body mass by the gravity in the place given.

On Earth, an astronaut that is 70kg weights 70kg * 9.8 m/s² = 686N

On the Moon, the same astronaut would weight 70kg * 9.8 m/s² * 1/6 = 114,3 N

So, the astronaut’s weight decreases because the moon’s gravitational acceleration is less than Earth’s.

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Answer:

Determinism

Explanation:

Rocky believes in himself and this is not a physics question

4 0
3 years ago
A wire of length 6cm makes an angle of 20° with a 3 mT
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Answer:

Approximately 7.3 \times 10^{-3}\; \rm A (approximately 7.3\; \rm mA) assuming that the magnetic field and the wire are both horizontal.

Explanation:

Let \theta denote the angle between the wire and the magnetic field.

Let B denote the magnitude of the magnetic field.

Let l denote the length of the wire.

Let I denote the current in this wire.

The magnetic force on the wire would be:

F = B \cdot l \cdot I \cdot \sin(\theta).

Because of the \sin(\theta) term, the magnetic force on the wire is maximized when the wire is perpendicular to the magnetic field (such that the angle between them is 90^\circ.)

In this question:

  • \theta = 20^\circ (or, equivalently, (\pi / 9) radians, if the calculator is in radian mode.)
  • B = 3\; \rm mT = 3 \times 10^{-3}\; \rm T.
  • l = 6\; \rm cm = 6 \times 10^{-2}\;\rm m.
  • F = 1.5\times 10^{-4}\; \rm N.

Rearrange the equation F = l \cdot I \cdot \sin(\theta) to find an expression for I, the current in this wire.

\begin{aligned} I &= \frac{F}{l \cdot \sin(\theta)} \\ &= \frac{3\times 10^{-3}\; \rm T}{6 \times 10^{-2}\; \rm m \times \sin \left(20^{\circ}\right)} \\ &\approx 7.3 \times 10^{-3}\; \rm A = 7.3 \; \rm mA\end{aligned}.

5 0
3 years ago
If sound waves require a medium (material) to vibrate in order to produce a sound, can sound waves travel in outer space? Why or
soldier1979 [14.2K]

Sound waves requires a medium (material) to vibrate in order to produce a sound. So sound waves cannot travel in outer space as it is vacuum.

8 0
3 years ago
In each case, lifting or pushing, why must you exert a force to move the object? Q1-2: How much more effort is required to lift
musickatia [10]

Answer:

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Explanation:

A force is required to move an object because the object will stay at rest until a force is applied.

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The effort required to lift or push two masses instead of one depends on the desired effect. For the same kinetic energy, no more effort is required. For the same momentum, half the effort is required for two masses. For the same velocity, double the effort is required.

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The components of vector à are:
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Answer:

|A| = √(Ax)^2 + (Ay)^2

|A| = √(7.6)^2 + (-6.4)^2

|A| = √98.72

|A| = 9.9

6 0
3 years ago
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