Answer:
Minimum coefficient of kinetic friction between the surface and the block is 
.
Explanation:
Given:
Mass of the block = M
Spring constant = k
Distance pulled = x
According to the question:
<em>We have to find the minimum co-efficient of kinetic friction between the surface and the block that will prevent the block from returning to its equilibrium with non-zero speed. </em>
So,
From the FBD we can say that:
⇒ Normal force, 
<em>...equation(i)</em>
⇒ Elastic potential energy, 
= 
<em> ...equation (ii)</em>
⇒ Frictional force, 
= 
<em> ...equation (iii)</em>
⇒ Plugging (i) in (iii).
⇒ 
Now,
⇒ As we know that the energy lost due to friction is equivalent to PE .
⇒ 
<em>...considering PE as</em> 
or 
.
Arranging the equation.
⇒ 
⇒ 
<em>...eliminating x from both sides.</em>
⇒ 
<em>...dividing both sides wit Mg.</em>
Minimum coefficient of kinetic friction between the surface and the block is .
Answer:
Ionic Compound
Explanation:
To identify the type of chemical bond in a molecule, look at the atoms that make up the compound. If there are two nonmetals, it is a covalent bond. If the two atoms are metals, it is a metallic bond. If one atom is a metal and the other is a nonmetal, it is an ionic bond. Ionic compounds are also known as salts. You can identify KBr as an ionic compound because potassium is a metal and a salt.
Hope this helps
-981N would be the reaction force of a person be that stands completely still with a mass of 100 kg.
An opposing force to an action force is referred to as a reaction force. The response force that results from surface engagement and adhesion while sliding is known as friction. Usually, the activities of applied forces result in reaction forces and reaction moments.
As,
F = ma
where, F = force
m = mass of object
a = acceleration due to gravity
Plugging in the values we get,
F = 100kg × 9.81m/s
F = 981 N
Since, reaction force acts opposite to action force so the correct answer is -981N.
Learn more about force here;
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Answer:
T = 2490 newton
Explanation:
Given that,
Mass of a person, m = 50 Kg
Speed of the swing at the lowest point, v = 10 m/s
Length of the rope, r = 2.5 m
Tension formula is given by
T = mg + ma N
where, T - Tension in the string
m - mass of the body
g - acceleration due to gravity
a - acceleration of the body
Since the person is swinging, the acceleration of the body is given by
a = v²/r m/s²
= 10/2.5 m/s²
a = 40 m/s²
Substituting in T
T = 50 Kg x 9.8 m/s² + 50 Kg X 40 m/s²
= 490 + 2000 Kg m/s²
T = 2490 newton
Therefore the tension in the rope is 2490 newton
