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Alenkinab [10]
3 years ago
6

In which stage of a star's life cycle, does gravity and fusion become balanced, and an adult star forms?

Physics
1 answer:
V125BC [204]3 years ago
8 0

Answer:

im guessing red giant-

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Four charges are on the four corners of a square. Q1 = +5μC, Q2 = -10μC, Q3 = +5μC, Q4 = -10μC. The side length of the square is
Marat540 [252]

Answer:

Explanation:

Electric field due to a point charge Q at a point at distance d is given by the relation

E = \frac{K\times Q}{d^2}

Since Q1 and Q2 are of the same magnitude and distance , so they will create eletric field of same magnitude. Similarly field due to rest of the charges will also be same.

The charges are situated on the corners of a square in such a way that

equal charges of Q1 and Q3 are situated on the diametrically  opposite corners of the square. Fields due to these two charges will be equal and opposite in direction. Therefore net field due to these two  charges will be zero.  

On the same ground, we can say that field due to Q2 and Q4 at the centre will be equal and opposite and therefore they will cancel out each other. Net field at the centre will be zero

Overall, net field due to all the four charges will be zero

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4 years ago
9. If you placed the contents of a packet of powdered iced tea mix into a bottle of water and shook it, which of the following w
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 The water would be solvent. Its your answer!
4 0
3 years ago
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Humans must depend on the environment for their survival.<br> True<br> False
Alisiya [41]

Answer:

true

Explanation:

with out trees we would have no air with out animals the envirounment would slowly decay

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3 years ago
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A scientist proposed a hypothesis that burning coal at higher altitudes would release less pollution. The data the scientist col
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6 0
3 years ago
At some distance from a point charge, the electric potential is 635.0 V and the magnitude of the electric field is 189.0 N/C. Fi
Nataliya [291]

Answer:

The distance from the charge is 3.35 m.                

Explanation:

Given that,

Electric potential, V = 635 V

Magnitude of electric field, E = 189 N/C

We need to find the distance from the charge. We know that the relation between electric field and electric potential is given by :

E=\dfrac{V}{d}

d is the distance from charge

d=\dfrac{V}{E}\\\\d=\dfrac{635}{189}\\\\d=3.35\ m

So, the distance from the charge is 3.35 m. Hence, this is the required solution.

8 0
3 years ago
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