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Anastaziya [24]
2 years ago
11

Jonathan must lift a 3000n rock using a lever. jonathan uses 300n of force to push down on the lever to move the rock. what is t

he ratio of the load to effort in this case?a)1:3b)3:1c)1:10eliminated)10:1
Physics
1 answer:
-Dominant- [34]2 years ago
3 0
The load is the weight of the rock that Jonathan lifts:
L=3000 N
The effort instead is the force applied in input to the lever in order to lift the rock:
E=300 N

So, the ratio between load and effort for this exercise is
\frac{L}{E}= \frac{3000 N}{300 N}=10
So, the ratio is 10:1.
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a=\frac{qE}{m}=\frac{(1.6*10^{-19}C)(4.0*10^2N/C)}{9.1*10^{-31}kg}=7.03*10^{13}\frac{m}{s^2}

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x_{max}=v_o\sqrt{\frac{2d}{a}}             (2)

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You replace the values of the parameters in the equation (2):

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The horizontal distance traveled by the electron is 9.5cm

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3 years ago
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