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4 years ago

HELP ASAP PLEASE !!!!!!!!!!!!!!

Mathematics

1 answer:

Damm [24]4 years ago

3 0

Answer:

Step-by-step explanation:

Think of drawing a right triangle, with the hypotenuse connected to points A and B. The hypotenuse, or the distance between A and B is 2√10. 2√10 is the same thing as √40. Thus, because of Pythagorean theorem, a^2 + b^2 = 40. One combination would be a=2 and b = 6 and another would be a = 6 and b = 2. Thus, the two places point B could be are (3,7) and (7,3).

Hope it helps <3

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On 5 days, lisa swam 650 meters, 675 meters, 725 meters, 800 meters, and 900 meters. What was her average distance per day?

zlopas [31]

Answer:

Her average per day was 750 meters.

Step-by-step explanation:

To find the average, add all the numbers up in the set and divide by how many numbers there are.

650 + 675 + 725 + 800 + 900 = 3750. Divide it by 5 and you get 750

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3 years ago

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3 years ago

Evaluate7.2÷0.38.(Round to the hundredth place as needed.)

polet [3.4K]

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Step-by-step explanation:

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3 years ago

Two planes left simultaneously from the same airport and headed in the same direction towards another airport 3600 km away. The

ExtremeBDS [4]

Answer:

800 kph
600 kph

Step-by-step explanation:

Equation

Let s represent the speed of the faster plane. Then its travel time is ...

time = distance/speed = 3600/s

travel time for the slower plane is ...

time = distance/speed = 3600/(s -200)

The difference in these times is 1.5 hours, so we have ...

3600/(s -200) -3600/s = 1.5

Solution

Multiplying by (2/3)s(s -200), we get ...

2400(s) -2400(s -200) = s(s -200)

s^2 -200s -480000 = 0 . . . . . . . . . . rewrite in standard form

(s -800)(s +600) = 0 . . . . . . . . . . . . . factor

The positive value of s that makes a factor zero is s = 800.

Conclusion

The speed of the faster plane was 800 km/h; of the slower plane, 600 km/h.

_____

Check

The travel time for the faster plane was 3600/800 = 4.5 hours. For the slower plane, 3600/600 = 6 hours, a difference of 1.5 hours.

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3 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

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