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What is the energy change when 78.0 g of Hg melt at −38.8°C
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Answer:
Rate constant of the reaction is .
Explanation:
A + B + C → D + E
Let the balanced reaction be ;
aA + bB + cC → dD + eE
Expression of rate law of the reaction will be written as:
Rate(R) of the reaction in trail 1 ,when :
...[1]
Rate(R) of the reaction in trail 2 ,when :
...[2]
Rate(R) of the reaction in trail 3 ,when :
...[3]
Rate(R) of the reaction in trail 4 ,when :
...[4]
By [1] ÷ [2], we get value of c ;
c = 1
By [3] ÷ [4], we get value of b ;
b = 0
By [2] ÷ [3], we get value of a ;
a = 2
Rate law of reaction is :
Rate constant of the reaction = k