Answer: 5,640 s (94 minutes)
Explanation:
the tangential speed of the HST is given by
(1)
where
is the length of the orbit
r is the radius of the orbit
T is the orbital period
In our problem, we know the tangential speed: . The radius of the orbit is the sum of the Earth's radius and the distance of the HST above Earth's surface:
So, we can re-arrange equation (1) to find the orbital period:
Dividing by 60, we get that this time corresponds to 94 minutes.
Answer:
The person can jump 48 m on the Moon
Explanation:
The question parameters are;
The maximum long jump distance of a person on Earth, = 3 m
The acceleration due to gravity on the Moon = 1 ÷ 16 of that on Earth
The distance the person can jump on the Moon is given as follows;
A person performing a jump across an horizontal distance on Earth (under gravitational force) follows the path of the motion of a projectile
The horizontal range, , of a projectile motion is found by using the following formula
Where;
g = The acceleration due to gravity = 9.8 m/s²
Therefore, we have;
u² = 3 m × 9.8 m/s² = 29.4 m²/s²
Therefore, on the Moon, we have;
The acceleration due to gravity on the Moon, = 1/16 × g
∴ = 1/16 × g = 1/16 × 9.8 m/s² ≈ 0.6125 m/s²
The maximum distance the person can jump on the Moon with the same velocity which was used on Earth is ≈ 48 m