Ask question

Ask question

All categories

3 years ago

9

1) How old is a bone in which the Carbon-14 in it has undergone 8 half-lives?

1 answer:

gladu [14]3 years ago

3 0

1) How old is a bone in which the Carbon-14 in it has undergone 8 half-lives?

Using the graph form the picture you count 8 times the halving of C¹⁴ and you arrive at 45600 years.

2) In the process of radiocarbon dating, the fixed period of radioactive decay used to determine age is called the half-life.

3) A certain byproduct in nuclear reactors, 210Po, decays to become 206Pb. After a time period of about 276 days, only about 25% of an original sample of 210Po remains. The remainder has decayed to 206Pb. Determine the approximate half-life of 210Po.

What the problem is telling you is that at 276 days only 25% original sample remains. If you divide the number of days by two the quantity of original sample will be multiplied by two, and you will have 138 days and 50% of original sample. This is the answer because the the half-life of a isotope is the time in which 50% of original quantity of radioactive atoms will disintegrate.

You might be interested in

If you observe with the microscope that a cell contains chloroplasts can you conclude that this is a plant cell?

shusha [124]

Obviously since plant cell contains chloroplasts.

8 0

3 years ago

The compound adrenaline contains 56.79% c, 6.56% h, 28.37% o, and 8.28% n by mass. what is the empirical formula for adrenaline?

Phoenix [80]

To determine the empirical formula of the compound given, we need to determine the ratio of each element in the compound. To do that we assume to have 100 grams sample of the compound with the given composition. Then, we calculate for the number of moles of each element. We do as follows:<span>
mass    moles
C 56.79 4.73
H 6.56 6.50
O 28.37 1.77
N 8.28 0.59

Dividing the number of moles of each element with the smallest value, we will have the empirical formula:

</span> moles ratio
C 4.73 / 0.59 8
H 6.50   / 0.59 11
O   1.77   / 0.59 3
N    0.59   / 0.59 1<span>
</span><span>
The empirical formula would be C8H11O3N.</span>

8 0

3 years ago

A student weighs out 0. 0422 g of magnesium metal. The magnesium metal is reacted with excess hydrochloric acid to produce hydro

lutik1710 [3]

The student weighs out 0.0422 grams of the metal magnesium, thus we can figure that the more's, the magnesium he used, is the mass of the magnesium over the more mass, which is 0.024422.
That is approximately 0.001758.
Furthermore, it claims that too much hydrochloric acid causes the metal magnesium to react, producing hydrogen gas.
The volume of collected gas is 43.9 cc, the mastic pressure is 22 cc, and a sample of hydrogen gas is collected over water in a meter.

<h3>Is it true that calculations made utilizing experimental and gathered data result in a percent error? </h3>

Consequently, we are aware that magnesium and chloride react.
We create 1 as the reaction ratio is 1:2.
The hydrogen and 1 are more.
Magnesium chloride is more.
Therefore, based on this equation, we can infer that the amount of hydrogen that would be created in this scenario is greater than the amount of magnesium present here, or 0.001758 more.
Among hydrogen, there is.
\Once we convert the temperature from 32 Celsius to kelvin, we can tell you that the temperature is actually about 5.15 kelvin.
The gas has a volume of 43 in m, which is equal to 0.0439 liter and indicates that the pressure is approximately 832 millimeter.
Mercury, which is 2 times 13332 plus ca, or roughly 110922.24 par, is a mathematical constant.
So, in this instance, we are aware that p v = n r t.
The r in this case equals p v over n t, thus we want to determine the r.
So p is 110922.24. The temperature is 305.15 and the V is 0.04 over the n is 0.001758.
Let's proceed with the calculations right now.
In this instance, you will discover that the solution is 9.077 times 10; that is all there is to it.

To learn more about Magnesium chloride reactions visit:

brainly.com/question/27891157

#SPJ4

3 0

2 years ago

What volume of 0.152 M KMnO4 solution would completely react with 20.0 mL of 0.381 M FeSO4 solution according to the following n

ANEK [815]

<u>Answer:</u> The volume of permanganate ion (potassium permanganate) is 10.0 mL

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of ferrous sulfate solution = 0.381 M

Volume of solution = 20.0 mL = 0.020 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.381M=\frac{\text{Moles of ferrous sulfate}}{0.020L}\\\\\text{Moles of ferrous sulfate}=(0.381mol/L\times 0.020L)=0.00762mol$

For the given chemical equation:

$5Fe^{2+}+8H^++MnO_4^-\rightarrow 5Fe^{3+}+Mn^{2+}+4H_2O$

By Stoichiometry of the reaction:

5 moles of iron (II) ions (ferrous sulfate) reacts with 1 mole of permanganate ion (potassium permanganate)

So, 0.00762 moles of iron (II) ions (ferrous sulfate) will react with = $\frac{1}{5}\times 0.00762=0.00152mol$ of permanganate ion (potassium permanganate)

Now, calculating the volume of permanganate ion (potassium permanganate) by using equation 1, we get:

Molarity of permanganate ion (potassium permanganate) = 0.152 M

Moles of permanganate ion (potassium permanganate) = 0.00152 mol

Putting values in equation 1, we get:

$0.152mol/L=\frac{0.00152mol}{\text{Volume of permanganate ion (potassium permanganate)}}\\\\\text{Volume of permanganate ion (potassium permanganate)}=\frac{0.00152mol}{0.152mol/L}=0.01L=10.0mL$

Hence, the volume of permanganate ion (potassium permanganate) is 10.0 mL

3 0

3 years ago

Which state of matter undergoes changes in volume most easily

lina2011 [118]

Gases and plasma's undergo changes in volume most easily<span>. In contrast, liquids and solids have fixed volumes, although liquids do not have fixed shapes. Gases and plasma's expand or contract to fill their containers.</span><span />

8 0

3 years ago