Answer:
![\dfrac{\mu_A}{\mu_G}=0.197](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmu_A%7D%7B%5Cmu_G%7D%3D0.197)
Explanation:
given,
Speed of a wave on violin A = 288 m/s
Speed on the G string = 128 m/s
Force at the end of string G = 110 N
Force at the end of string A = 350 N
the ratio of mass per unit length of the strings (A/G). = ?
speed for string A
.......(1)
speed for string G
........(2)
Assuming force is same in both the string
now,
dividing equation (2)/(1)
![\dfrac{v_G}{v_A}=\dfrac{\sqrt{\dfrac{F_G}{\mu_G}}}{\sqrt{\dfrac{F_A}{\mu_A}}}](https://tex.z-dn.net/?f=%5Cdfrac%7Bv_G%7D%7Bv_A%7D%3D%5Cdfrac%7B%5Csqrt%7B%5Cdfrac%7BF_G%7D%7B%5Cmu_G%7D%7D%7D%7B%5Csqrt%7B%5Cdfrac%7BF_A%7D%7B%5Cmu_A%7D%7D%7D)
![\dfrac{v_G}{v_A}=\dfrac{\sqrt{\mu_A}}{\sqrt{\mu_G}}](https://tex.z-dn.net/?f=%5Cdfrac%7Bv_G%7D%7Bv_A%7D%3D%5Cdfrac%7B%5Csqrt%7B%5Cmu_A%7D%7D%7B%5Csqrt%7B%5Cmu_G%7D%7D)
![\dfrac{128}{288}=\dfrac{\sqrt{\mu_A}}{\sqrt{\mu_G}}](https://tex.z-dn.net/?f=%5Cdfrac%7B128%7D%7B288%7D%3D%5Cdfrac%7B%5Csqrt%7B%5Cmu_A%7D%7D%7B%5Csqrt%7B%5Cmu_G%7D%7D)
![\dfrac{\mu_A}{\mu_G}=0.197](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmu_A%7D%7B%5Cmu_G%7D%3D0.197)
Answer:
pressure= force/area
A solid resting on a horizontal surfaceexerts a normal contactforce equals to its weight. The pressure of the solid on the surface depends on the area of contact. (b) the area of contact between the two surfaces. The greater the force or the smaller the area the greater the pressure.
Answer:
40000 N/m²
Explanation:
Applying,
P = F/A................... Equation 1
Where P = Pressure, F = Force, A = Area.
From the question,
The force(F) exerted by the person's foot is thesame as it's weight.
F = W = mg............ Equation 2
Where m = mass of the person, g = acceleration due to gravity.
Substitute equation 2 into equation 1
P = mg/A................ Equation 3
Given: m = 60 kg, g = 10 m/s², A = 150 cm² = (150/10000) m² = 0.015 m²
Substitute these values into equation 3
P = (60×10)/0.015
P = 600/0.015
P = 40000 N/m²
Answer:
![v = 10.75\,\frac{m}{s}](https://tex.z-dn.net/?f=v%20%3D%2010.75%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)
Explanation:
The system ball-pin is modelled by the Principle of Moment Conservation:
![(9\,kg)\cdot (15\,\frac{m}{s} ) + (0.85\,kg)\cdot (0\frac{m}{s} ) = (9\,kg)\cdot v + (0.85\,kg)\cdot (45\,\frac{m}{s} )](https://tex.z-dn.net/?f=%289%5C%2Ckg%29%5Ccdot%20%2815%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%20%2B%20%280.85%5C%2Ckg%29%5Ccdot%20%280%5Cfrac%7Bm%7D%7Bs%7D%20%29%20%3D%20%289%5C%2Ckg%29%5Ccdot%20v%20%2B%20%280.85%5C%2Ckg%29%5Ccdot%20%2845%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29)
The velocity of the bowling ball after the collision is:
![v = 10.75\,\frac{m}{s}](https://tex.z-dn.net/?f=v%20%3D%2010.75%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)
The amount of force required to stretch or compress the spring is known as the spring force. Its unit is Newton(N). Force is needed to stretch spring is 10.2 N.
<h3>What is spring force?</h3>
The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is
F = kx
The given data in the problem is;
F is the spring force =?
K is the spring constant= 8.5 N/m
x is the length by which spring got stretched = 1.2m
![\rm F_S=Kx \\\\ \rm F_S=8.5 \times 1.2 \\\\ \rm F_S=10.2 N](https://tex.z-dn.net/?f=%5Crm%20F_S%3DKx%20%5C%5C%5C%5C%20%5Crm%20F_S%3D8.5%20%5Ctimes%201.2%20%5C%5C%5C%5C%20%5Crm%20F_S%3D10.2%20N)
Hence the force is needed to stretch the spring is 10.2 N.
To learn more about the spring force refer to the link;
brainly.com/question/4291098