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3 years ago

As sea floor spreading occurs, the oceanic plate _______.

Physics

1 answer:

Ira Lisetskai [31]3 years ago

8 0

Becomes older

Explanation:

As sea floor spreading occurs at divergent margins, the oceanic plate becomes older. Younger plate margin are the closest to the margin whereas the older plates bushes backward away from the spreading centers.

The idea that the sea floor spreads was postulated by Harry Hess shortly after the second world war around the 1960's.
At divergent margins new crust materials from the mantle are brought to the surface.
They crystallize and settle at the flanks of plate margins.
Older ones are pushed backward away from the margin into far away subduction zones.

Learn more:

Sea floor spreading brainly.com/question/9912731

#learnwithBrainly

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Which way will the people on the right move? Why? Plz answer

Scrat [10]

Probably to the right because the force on the left is greater and will therefore overpower the 2N force and push to the right

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2 years ago

If there is a 25 [lbs] of force acting on a 5 [lbs] of mass, what is the acceleration of that mass?

mihalych1998 [28]

Answer:

f = 25 lbs

m = 5 lbs

a =?

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2 years ago

During the first 6 years of its operation, the Hubble Space Telescope circled the Earth 37,000 times, for a total of 1,280,000,0

madreJ [45]

Answer:

$Kilometers\ in\ 1\ Orbit=\frac{1.28*10^9 Km}{3.7*10^4orbits}$

$Kilometers\ in\ 1\ Orbit=3.46*10^4 Km/Orbit$

Explanation:

Given Data:

Numbers of times Telescope cycled around the earth in 6 years=37,000 times

Total Distance traveled in 6 years by the Hubble Space Telescope=1,280,000,000 Km

Find:

Kilometers in one Orbit=?

Solution:

Kilometers in 37,000 Orbits=1,280,000,000 Km

Kilometers in 1 Orbit=1,280,000,000/37,000

In Scientific Notation:

$Kilometers\ in\ 3.7*10^4\ Orbits=1.28*10^9 Km$

$Kilometers\ in\ 1\ Orbit=\frac{1.28*10^9 Km}{3.7*10^4 orbits}$

Kilometers in 1 Orbit=34594.594 Km

Kilometers in 1 Orbit in Scientific notation:

$Kilometers\ in\ 1\ Orbit=3.46*10^4 Km$

8 0

3 years ago

3) Principles of rectilinear proportion of light 9

8_murik_8 [283]

Answer:Principle of rectilinear propagation of light

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7 0

1 year ago

During takeoff, an airplane climbs with a speed of 195 m/s at an angle of 15° above the horizontal. The speed and angle constitu

matrenka [14]

Answer:

The horizontal component of the velocity is 188 m/s

The vertical component of the velocity is 50 m/s.

Explanation:

Hi there!

Please, see the figure for a graphic description of the problem. Notice that the x-component of the vector velocity (vx), the y-component (vy) and the vector velocity form a right triangle. Then, we can use trigonometry to obtain the magnitude of vx and vy:

We can find vx using the following trigonometric rule of a right triangle:

cos α = adjacent / hypotenuse

cos 15° = vx / 195 m/s

195 m/s · cos 15° = vx

vx = 188 m/s

The horizontal component of the velocity is 188 m/s

To calculate the y-component we will use the following trigonometric rule:

sin α = opposite / hypotenuse

sin 15° = vy / 195 m/s

195 m/s · sin 15° = vy

vy = 50 m/s

The vertical component of the velocity is 50 m/s.

4 0

3 years ago